Dalton
Dalton's theory was the first scientific theory because it relied on scientific investigative processes.
Answer:
HF + LiOH = LiF + H2O.
Explanation:
Hydofluoric acid is a weak acid the solution would be slightly basic due to the following equilibrium (condition in the course of a reversible chemical reaction in which no net change in the amounts of reactants and products occurs.)
Hope that helps. x
Answer : The orbitals that are used to form each indicated bond in citric acid is given below as per the attachment.
Answer 1) σ Bond a: C
O
.
Explanation : The sigma bonds in the 'a' position involves carbon atom which undergoes
hybridisation and has
orbitals of carbon and as well as oxygen atoms involved in the bonding.
Answer 2) π Bond a: C has π orbitals and O also has π orbitals.
Explanation : The pi-bond at the 'a'position has carbon and oxygen atoms which undergoes pi-bond formation. And has pi orbitals of oxygen and carbon involved in the bonding process.
Answer 3) Bond b: O
H has only S orbital involved in bonding.
Explanation : The bonding at 'b' position involves oxygen and hydrogen atoms in it. It has
hybridized orbitals and S orbital of hydrogen involved in the bonding.
Answer 4) Bond c: C
O
Explanation : The bonding involved at 'c' position has carbon and oxygen atoms involved in it. Both the atoms involves the orbitals of
hybridized bonds.
Answer 5) Bond d: C
C 
Explanation : The bonding involved at the position of 'd' involves two carbon atoms. Therefore, they undergo
hybridization. The orbitals involved in this hybridization are also
.
Answer 6) Bond e: C1 containing O
C2 
Explanation : The bonding at the 'e' position involves two carbon atoms on is containing oxygen with double bonds and the C2 carbon atom. The carbon containing oxygen has
hybridized orbitals involved in the bonding; whereas C2 carbon ha
orbitals.
Answer is: 120 days <span>will it take for decay.
</span>Half-life <span>is
the time required for a quantity (in this example number of radioactive nuclei of lincolnium) to
reduce to half its initial value.
</span>Initial mass of sample: 30 grams.
After first half-life (60 days): 50% · 30 g ÷ 100% = 15 g.
After second half-life (120 days): 0.5 · 15 g = 7.5 g.