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posledela
3 years ago
9

When coal is burned completely into carbon dioxide and other gases, the total amount of matter of the gases _____.

Chemistry
1 answer:
Olenka [21]3 years ago
8 0

Answer:

must be equal to the amount of matter of the coal.

Explanation:

According to the law of conservation of matter, which states that matter can neither be created nor destroyed no matter how transformed it is. This means that the total amount of the reactants must equate the total amount of products.

In this question involving a reaction that causes a change of state from solid (coal) to gaseous (CO2 and other gases), in order to obey the law of conservation of mass, the total amount of the matter of the gases (products) must be equal to that amount of matter of the coal (reactants).

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Umnica [9.8K]

Answer:

Ali is incorrect.

Explanation:

Ali is wrong because the climate is a study of the weather pattern over a long period of time. You cannot look outside one day and determine the climate because the climate is long-term.

She could say the weather is rainy, because that is short term, but not the climate.

6 0
3 years ago
Cuales eran los objetos fundamentales de los alquimistas?
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Los alquimistas querían cambiar el plomo en oro. Esto es, para crear algo de nada
4 0
4 years ago
Which layer is the oldest layer?<br><br><br> PLEASE ANSWER
exis [7]

Answer:

rock strata farthest from the ground surface are the oldest

THERE U GO

<h3>I HOPE IT HELPS YOU </h3>

<h2>PLEASE MARK ME BRAINLIEST IF YOU ARE SATISFIED BY THE ANSWER:)</h2>
7 0
2 years ago
Combustion of hydrocarbons such as pentane (C5H12) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's
zhuklara [117]

2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)

Explanation:

Balanced chemical equation for combustion of pentane C₅H₁₀:

C₅H₁₀ (l) + (15/2) O₂ (g) → 5 CO₂ (g) + 5 H₂O (g)

to get integer numbers for the stoechiometric coefficients we multiply with 2:

2 C₅H₁₀ (l) + 15 O₂ (g) → 10 CO₂ (g) + 10 H₂O (g)

where:

(l) - liquid

(g) - gas

Learn more about:

combustion of hydrocarbons

brainly.com/question/13691565

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5 0
3 years ago
Read 2 more answers
1. What volume of gas (NU) is formed by the interaction of 13 g of zinc with 400 g of sulfuric acid solution with a mass fractio
Svetllana [295]

Answer:

4.5L of gas are produced

Explanation:

Based on the reaction:

Zn + H2SO4 → ZnSO4 + H2(g)

<em>Where 1 mole of Zn reacts with 1 mole of sulfuric acid to produce 1 mole of H2, the gas</em>

<em />

To solve this question we must find the moles of each reactant in order to find limiting reactant and, thus, the moles of H2 produced. Then using PV=nRT we can find the volume of the gas:

<em>Moles Zn -Molar mass: 65.38g/mol-</em>

13g * (1mol / 65.38g) = 0.20 moles Zn

<em>Moles H2SO4 -Molar mass: 98g/mol-</em>

400g * 10% = 40g H2SO4 * (1mol / 98g) = 0.41 moles H2SO4

As the ratio of the reaction is 1:1, the limiting reactant is Zn and the moles produced of H2 are 0.20 moles

Using PV = nRT; V = nRT/ P

<em>Where V is the volume of the gas </em>

<em>n are the moles = 0.20 moles</em>

<em>R is gas constant = 0.082atmL/molK</em>

<em>T is absolute temperature = 273.15K at STP</em>

<em>P is pressure = 1atm at STP</em>

<em />

V = 0.20mol*0.082atmL/molK*273.15K / 1atm

V = 4.5L of gas are produced

<em />

5 0
3 years ago
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