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3 years ago

assuming oxygen behaves like an ideal gas, what volume in liters would 3.50 moles of oxygen gas occupy at STP?

Chemistry

1 answer:

astra-53 [7]3 years ago

6 0

Answer:

78.4L

Explanation:

1 mole of any gas is found to occupy 22.4L at stp. This also indicates that 1mole of oxygen occupy 22.4L.

Therefore,

3.50 moles of oxygen Will occupy = 3.5x22.4 = 78.4L

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3 years ago

Please help with #2 and #3

Vaselesa [24]

Answer:

2. $V_2=17L$

3. $V=82.9L$

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

$\frac{V_2}{T_2}=\frac{V_1}{T_1}$

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

$V_2=\frac{V_1T_2}{T_1}$

Therefore, we plug in the given data to obtain:

$V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L$

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

$V=\frac{nRT}{P}$

Therefore, we plug in the data to obtain:

$V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L$

Best regards!

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3 years ago

Why does a physical change occur when iodine is heated?

makkiz [27]

Answer:

Explanation:

when few crystals of iodine are added to test tube

the test tube gets heated and turns into a gas

which later soldifies to a liquid

I hope this helps

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3 years ago