Answer:
4. Principal and Azimuthal (subsidiary) quantum number
5.Principal, Azimuthal (subsidiary), and magnetic quantum number
6. 10 electrons
7. 32 electrons
8. 36 electrons
Explanation:
4. Principal and Azimuthal (subsidiary) quantum number because in 4d, 4 represent principal quantum number and d- represents azimuthal quantum number (having l- value as 3)
5.Principal, Azimuthal (subsidiary), and magnetic quantum number are the first three because 2 stands for principal, s-for azimuthal (l=0) and magnetic quantum number for s- orbital= 0
6. 10 electrons, because for sublevel with l= 3, is a d-sub-level, and d- can take 10-electrons
7. 32 electrons, using the relationship 2×n^2 for the maximum number of electrons in a shell,
,n= 4 , hence 2×4^2= 32
8. 36 electrons, because n=4 and n= 3 can have the maximum configuration of [Ar]4s^2 3d^10 4p^6
This will sum up to 36- electrons, since Argon has 18 -electrons.
18+2+10+6=36 electrons
It's the first option choice on Plato
I think it’s either 1 or 2 !!
Answer:
The answer to your question is given below.
Explanation:
From the question given above, the following data were obtained:
Br₂ (l) —> Br₂(g)
Enthalpy change (ΔH) = 30.91 KJ/mol
Entropy change (ΔS) = 93.3 J/mol·K
Boiling temperature (T) =?
Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:
1 KJ/mol = 1000 J/mol
Therefore,
30.91 KJ/mol = 30.91 × 1000
30.91 KJ/mol = 30910 J/mol
Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.
Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:
Enthalpy change (ΔH) = 30910 J/mol
Entropy change (ΔS) = 93.3 J/mol·K
Boiling temperature (T) =?
ΔS = ΔH / T
93.3 = 30910 / T
Cross multiply
93.3 × T = 30910
Divide both side by 93.3
T = 30910 / 93.3
T = 331.29 K
Thus, the boiling temperature of bromine is 331.29 K
