9.there are thermal cups that we use
<span>Deionized water is regarded as pure water, which is a compund, not a mixture. A mixture requires that there are 2 different pure componds combined, with a homogeneous mixture requiring that the apperance is consistent and uniform. Because it is a compound, deionized water cannot be a homogenous mixture. instead, an example of a homogeneous mixture would be salt water</span>
It is 10 kg, because the gravity of the Earth is 10N/kg. Mark Brainliest.
Answer:
![p_2=347.9kPa](https://tex.z-dn.net/?f=p_2%3D347.9kPa)
Explanation:
Hello,
In this case, we use the Gay-Lussac's law which allows us to understand a gas' pressure-temperature behavior as a directly proportional relationship:
![\frac{p_1}{T_1}= \frac{p_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7Bp_1%7D%7BT_1%7D%3D%20%5Cfrac%7Bp_2%7D%7BT_2%7D)
Whereas it is convenient to use the pressure in kPa and the temperature in kelvins in order to compute the required resulting pressure, therefore:
![p_1=55.0psi*\frac{6.89476kPa}{1psi} =379.2kPa\\T_1=30.0+273.15=303.15K\\T_2=5.0+273.15=278.15K](https://tex.z-dn.net/?f=p_1%3D55.0psi%2A%5Cfrac%7B6.89476kPa%7D%7B1psi%7D%20%3D379.2kPa%5C%5CT_1%3D30.0%2B273.15%3D303.15K%5C%5CT_2%3D5.0%2B273.15%3D278.15K)
Thus, we obtain:
![p_2= \frac{p_1T_2}{T_1}=\frac{379.2kPa*278.15K}{303.15K}\\ \\p_2=347.9kPa](https://tex.z-dn.net/?f=p_2%3D%20%5Cfrac%7Bp_1T_2%7D%7BT_1%7D%3D%5Cfrac%7B379.2kPa%2A278.15K%7D%7B303.15K%7D%5C%5C%20%5C%5Cp_2%3D347.9kPa)
Best regards.