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2 years ago

Plz help!! I need an answer ASAP

Mathematics

2 answers:

defon2 years ago

4 0

1 Add
5
y
5y to both sides.
2
x
−
3
=
5
y
2x−3=5y

2 Add
3
3 to both sides.
2
x
=
5
y
+
3
2x=5y+3

3 Divide both sides by
2
2.
x
=
5
y
+
3
2
x=
2
5y+3

KiRa [710]2 years ago

3 0

Answer:

-5/2

Step-by-step explanation:

-5y=-2x+3

y=2/5x-3/5

The slope is negative recipricol

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Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

4 0

3 years ago

Help me and you will get more points

AlekseyPX

z = 3m - 2n

Step-by-step explanation:

1000^m ÷ 100^n

Rewrite them in exponent form

That's

10^3m ÷ 10^2n

Since the bases are the same and they are dividing we subtract the exponents

That's

10^3m - 2n

Comparing it with 10^z

10^3m - 2n = 10^z

z = 3m - 2n

Hope this helps you

3 0

2 years ago

The functionâ€‹ s(t) represents the position of an object at time t moving along a line. Suppose s (3 )equals 156 and s (6 )equa

bixtya [17]

Answer: The average velocity of the object over the time interval [3,6] is 20.

Step-by-step explanation:

Since we have given that

s(3) = 156

s(6) = 216

We need to find the average velocity over the time interval [3,6].

So, average velocity becomes

$\dfrac{s(t_1)-s(t_0)}{t_1-t_0}\\\\=\dfrac{s(6)-s(3)}{6-3}\\\\=\dfrac{216-156}{3}\\\\=\dfrac{60}{3}\\\\=20$

Hence, the average velocity of the object over the time interval [3,6] is 20.

5 0

2 years ago

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Kaylis [27]

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Step-by-step explanation:

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2 years ago

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Romashka [77]

Answer:

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Step-by-step explanation:

-3×-3 = 3

3×-3 = -3

etc...

Hope this helps! :)

4 0

2 years ago

Read 2 more answers