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3 years ago

What is a household product, food, or drink with a ionic, polyatomic, or covalent compound?

Chemistry

1 answer:

Svetllana [295]3 years ago

6 0

Answer:

table salt

Explanation:

You might be interested in

How many moles are in 8.32 x 1024 molecules of CO2.

Andrews [41]

Answer:

<h2>13.82 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

$n = \frac{N}{L} \\$

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

$n = \frac{8.32 \times {10}^{24} }{6.02 \times {10}^{23} } \\ = 13.820598...$

We have the final answer as

<h3>13.82 moles</h3>

Hope this helps you

6 0

3 years ago

During the formation of an ionic compound, the element with the higher ionization energy will gain electrons.

Lesechka [4]

False because you have to take it out and do it right

8 0

4 years ago

Which medical condition(s) can prevent molecules from entering the cell?

kvasek [131]

Answer:

Explanation:

any type of spreading disease that kills

6 0

3 years ago

Read 2 more answers

A 25.0-mL sample of 0.150 M butanoic acid is titrated with a 0.150 M NaOH solution. What is the pH before any base is added? The

hoa [83]

HA ⇄ H⁺ + A⁻
so:
$\frac{[H^+][A^-]}{[HA]} = 1.5 x 10^{-5}$
and now:
$\frac{(x)(x)}{(0.150-x)}$ = 1.5 x 10⁻⁵
x is considered very small compared to 0.15
x² = 2.25 x 10⁻⁶
x = 1.5 x 10⁻³
So [H⁺] = 1.5 x 10⁻³
pH = - log [H⁺] = - log (1.5 x 10⁻³) = 2.83

7 0

3 years ago

A chemistry student weighs out 0.027 kg of an unknown solid compound X and adds it to 550. mL of distilled water at 30.° C. Afte

QveST [7]

Answer:

1. Yes

2.The solubility of X is 34.55g/L

Explanation:

Solubility of solute refers to how readily a solute will dissolve in a solvent at a particular temperature. Its the amount of moles or grams required to saturate 1dm $^{3}$ or 1 Litre of water.

From the problem, when the liquid was drained off and amount of X which didn't dissolve was measured, it weighed 0.008kg, this means out of 0.027kg, 0.027-0.008 actually dissolved

= 0.019kg*1000 = 19g.

if 19g is required to saturate 550mL at 30°C,

then $\frac{19*1000}{550}$ will saturate 1L

= 34.545g will saturate 1Litre

The solubility thus is 34.55g/L

5 0

3 years ago