The perforating canals run perpendicular to osteons. <br><br> a. True <br><br> b. False

If two objects A and B have the same kinetic energy but A has three times the momentum of B, what is the ratio of their inertias

Thepotemich [5.8K]

Answer:

$\frac{inertia_B}{inertia_A}=9$

Explanation:

First of all, let's remind that:

- The kinetic energy of an object is given by $K=\frac{1}{2}mv^2$ , where m is the mass and v is the speed

- The momentum of an object is given by $p=mv$

- The inertia of an object is proportional to its mass, so we can write $I=km$ , where k just indicates a constant of proportionality

In this problem, we have:

- $K_A = K_B$ (the two objects have same kinetic energy)

- $p_A = 3 p_B$ (A has three times the momentum of B)

Re-writing both equation we have:

$\frac{1}{2}m_A v_A^2 = \frac{1}{2}m_B v_B^2\\m_A v_A = 3 m_B v_B$

If we divide first equation by second one we get

$v_A = 3 v_B$

And if we substitute it into the first equation we get

$m_A (3 v_B)^2 = m_B v_B^2\\9 m_A v_B^2 = m_B v_B^2\\m_B = 9 m_A$

So, B has 9 times more mass than A, and so B has 9 times more inertia than A, and their ratio is:

$\frac{I_B}{I_A}=\frac{km_B}{km_A}=\frac{9m_A}{m_A}=9$

7 0

3 years ago

Scheduling comes before sequencing. In scheduling, we develop plans for our work centers where production activities occur. We l

ser-zykov [4K]

Answer: 89

Explanation:

4 0

3 years ago

The star Sirius has an apparent magnitude of -1.46 and appears 95-times brighter compared to the more distant star Tau Ceti, whi

dimaraw [331]

Answer:

(a) Apparent magnitude is the perceived brightness of an astronomical object

Absolute magnitude is the luminosity based on viewing an object from a 32.6 light-years distance

Bolometric magnitude is the total emitted radiation of a star

(b) The apparent magnitude of the star Tau Ceti = 3.51

(c) The distance between the Earth and Tau Ceti is 1.13 × 10¹⁴ km

Explanation:

(a) Apparent magnitude is an estimate of an astronomical objects' brightness as the object is perceived from the Earth

The absolute magnitude is the magnitude an object appears to have when viewed from a 32.6 light-years distance while having constant transfer of its luminosity that is not affected by cosmic dust and objects present in the line of sight

The bolometric magnitude of a star is the sum total of the star's radiation released over all electromagnetic spectrum wavelengths

(b) The apparent magnitude of the star Tau Ceti is found using the following equation;

$m_{2}-m_{1} = -2.512\times log\left (\dfrac{B_{2}}{B_{1}} \right )$

Where:

m₁ = Apparent magnitude of Tau Ceti

m₂ = Apparent magnitude of Sirius = -1.46

B₁ = Brightness of Tau Ceti

B₂ = Brightness of Sirius

$\left \dfrac{B_{2}}{B_{1}} \right = 95$

Hence we have;

$-1.46-m_{1} = -2.512\times log\left (95 \right )$

m₁ = -1.46 + 2.512 × log(95) = 3.51

The apparent magnitude of the star Tau Ceti = 3.51

(c) The distance between the Earth and Tau Ceti is found using the following equation;

$m-M = 5\times log\left (\dfrac{d}{10} \right )$

Where:

m = Apparent magnitude of Tau Ceti

M = Absolute magnitude of Tau Ceti = 5.69

d = The distance between the Earth and Tau Ceti

Which gives;

$3.51-5.69 = 5\times log\left (\dfrac{d}{10} \right )$

$\therefore \dfrac{d}{10} = 10^{-0.436} = 0.3664$

d = 10 × 0.3664 = 3.664 parsecs = 3.664 × 3.0857 × 10¹⁶ m

d = 1.13 × 10¹⁴ km.

4 0

3 years ago

While standing outdoors one evening, you are exposed to the following four types of electromagnetic radiation: yellow light from

Alona [7]

Answer: FM radio waves, AM radio waves, yellow light, micro waves

Explanation:

5 0

3 years ago

Read 2 more answers

An 8-inch dinner knife is sitting on a circular plate so that its ends are on the edge of the plate. if the minor arc that is in

Makovka662 [10]

When we form a right triangle connecting the edge of the knife to the center of the circle and the center of the knife to the center of the circle, the radius of the circle becomes the hypotenuse. Using the trigonometric function,
sin 60° = opposite / hypotenuse = 4 / hypotenuse
The value of the hypotenuse is 4.62 inches. Then, the diameter is twice this value which is 9.24 inches.

5 0

4 years ago

The perforating canals run perpendicular to osteons. a. True b. False