A horizontal line has a slope of 0. Remember the z in horizontal means zero. The slope of a vertical line is undefined.
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Answer:
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Step-by-step explanation:
F(x)=x^2+2x+1 & g(x)=3(x+1)^2
now, f(x)+g(x)
=x^2+2x+1+3(x+1)^2
=x^2+2x+1+3(x^2+2x+1)
=x^2+2x+1+3x^2+6x+3
=4x^2+8x+4<===answer(c)
next:
f(x)=x^2-1 & g(x)=x+3
now, f(g(x))=(x+3)^ -1
=x^2+6x+9-1
=x^2+6x+8<====answer(b)
i solve two of ur problems.
now try the 3rd one that is similar to no. 1
and try the last two urself.
Answer:
The Proof is given below.
Step-by-step explanation:
Given:
LN⊥KM,
KL≅ML
To Prove:
ΔKLN≅ΔMLN
Proof:
In Δ KLN and Δ MLN
KL ≅ ML ....……….{Given i.e Hypotenuse }
LN ≅ LN …………..{Reflexive Property}
∠ LNK ≅ ∠ LNM ……….{ LN ⊥ KM i.e Measure of each angle is 90° given}
Δ KLN ≅ Δ MLN ….{By Hypotenuse Leg Theorem}
....Proved
The answer is
graph A
Hope this helps :)
