Answer:
the limit does not exist
Step-by-step explanation:
As x approaches π/2 from below, tan(x) approaches +∞. A x approaches π/2 from above, tan(x) approaches -∞. These two limits are not the same, so the limit is said not to exist.
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For a limit to exist, it must be the same regardless of the direction of approach.
That would be 16 because all the others are multiples of 3.
-3(2x-4)+8x-8
-6x+12+8x-8
2x+4
x=2
Factor x^2 + x - 6
(x - 2)(x + 3) = 0
Solve for x
Ask yourself; When will (x - 2)(x + 3) equal zero?
When x - 2 = 0 or x + 3 = 0
Then solve for each of the two equations above
<em>x = 2, -3</em>
<u>Answer: C. 2, -3</u>
I did this but im not very good at it :( but i think the answer is either A or D sorry if im wrong :(
