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Blizzard [7]
3 years ago
7

Please can someone give me the Answers from one to 10 and explain how you get it in a notebook

Mathematics
1 answer:
amid [387]3 years ago
5 0

Answer/Step-by-step explanation:

1. (0, 3) and (-4, -3)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-3 - 3}{-4 - 0} = \frac{-6}{-4} = \frac{3}{2}

2. (2, -5) and (0, 5)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - (-5)}{0 - 2} = \frac{10}{-2} = -5

3. (-5, -5) and (-3, 5)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 -(-5)}{-3 -(-5)} = \frac{10}{2} = 5

4. (0, -5) and (5, 5)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{5 - (-5)}{5 - 0} = \frac{10}{5} = 2

5. (-4, 5) and (1, 0)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 5}{1 - (-4)} = \frac{-5}{5} = -1

6. (-5, 1) and (5, -4)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-4 - 1}{5 -(-5)} = \frac{-5}{10} = -\frac{1}{2}

7. (-1, 4) and (-2, 1)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{1 - 4}{-2 -(-1)} = \frac{-3}{-1} = 3

8. (-5, 1) and (5, 0)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 1}{5 - (-5)} = \frac{-1}{10} = -\frac{1}{10}

9. (-5, -2) and (5, -3)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{-3 -(-2)}{5 -(-5)} = \frac{-1}{10} = -\frac{1}{10}

10. (-3, 2) and (-5, 3)

Slope = \frac{y_2 - y_1}{x_2 - x_1} = \frac{3 - 2}{-5 -(-3)} = \frac{1}{-2} = -\frac{1}{2}

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<h3>What is the equation of line?</h3>

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Answer:

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Step-by-step explanation:

Part 1)

we know that

The measure of the inner angle is the semi-sum of the arcs comprising it and its opposite.

we have

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The arcs that comprise it and its opposite are arc SP and arc QR

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Part 2)

we know that

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In this problem we have that

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Part 3)

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The <u>Tangent-Tangent Theorem</u>  states that if from one external point, two tangents are drawn to a circle then they have equal tangent segments

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In this problem

PQ=PR

Part 4)

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The measurement of the outer angle is the semi-difference of the arcs it encompasses.

In this problem

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