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tino4ka555 [31]

3 years ago

8

The nuclides having the same number of

1 answer:

frez [133]3 years ago

6 0

Answer:

isotopes

Hope this helps

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If the length of the air column in the test tube is 14.0 cm, what is the frequency of this standing wave?

GaryK [48]

Answer:

f = 614.28 Hz

Explanation:

Given that, the length of the air column in the test tube is 14.0 cm. It can be assumed that the speed of sound in air is 344 m/s. The test tube is a kind of tube which has a closed end. The frequency in of standing wave in a closed end tube is given by :

$f=\dfrac{nv}{4l}$

$f=\dfrac{1\times 344}{4\times 0.14}$

f = 614.28 Hz

So, the frequency of the this standing wave is 614.28 Hz. Hence, this is the required solution.

4 0

4 years ago

N in-ground swimming pool has the dimensions shown in the drawing. It is filled with water to a uniform depth of 3.00 m. The den

Doss [256]

Answer:

The pressure is $P = 1.31*10^{5} \ Pa$

Explanation:

From the question we are told that

The depth of the swimming pool is $d = 3.00 \ m$

The density of water is $\rho = 1.00*10^{3} \ kg /m^3$

Generally the total pressure exerted on the bottom of the swimming pool is mathematically represented as

$P = P_o + \rho * g * h$

Here $P_o$ is the atmospheric pressure with value

$P_o = 101325 \ Pa$

So

$P = 101325 + [1000 * 9.8 * 3]$

=> $P = 130725 \ Pa$

=> $P = 1.31*10^{5} \ Pa$

7 0

3 years ago

Human population growth rates are increasing. Assuming that the biocapacity of earth does not change, what will need to happen t

iogann1982 [59]

I think it would need to decress bro

3 0

3 years ago

Read 2 more answers

how much thermal energy is absorbed by a copper water pipe with a mass of 2.3kg when its temperature is raised from 20.0 to 80.0

Sphinxa [80]

Explanation:

q = mCΔt

q = (2.3 kg) (385 J/kg/K) (80.0°C − 20.0°C)

q ≈ 53,000 J

q ≈ 53 kJ

3 0

3 years ago

Which of the following changes would double the force between two charged particles? O A. Decreasing the distance between the pa

jarptica [38.1K]

Let's check

$\\ \rm\dashrightarrow F=\dfrac{k}{q_1q_2}{r^2}$

$\\ \rm\dashrightarrow F\propto Q$

$\\ \rm\dashrightarrow F\propto \dfrac{1}{r^2}$

So

Option A and C can be used

6 0

2 years ago

Read 2 more answers