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3 years ago

What is friction and the types withe examples.

Physics

1 answer:

Blizzard [7]3 years ago

7 0

Explanation:

The answer is In the picture. Thanks.

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Determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.

ozzi

Answer:

The thrust is $6\times 10^6\ N$

Explanation:

Given that,

Mass of gas, $m=1.5\times 10^3\ kg$

The rate at which the gas is expelling, $\dfrac{dv}{dt}=4\times 10^{3}\ m/s$

We need to find the thrust produced by the gas.

We know that force is equal to the rate of change of momentum. So,

$F=\dfrac{p}{t}$

Also, p = mv

$F=\dfrac{mv}{t}$

So,

$F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N$

So, the thrust is $6\times 10^6\ N$

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4 years ago

The monomer used as the building block in polyethylene is? Ethene, ethane, monoethane, amino acids?

LuckyWell [14K]

<span>it's ethene and not an amino acid!!! amino acids form proteins as their polymers. </span>

6 0

4 years ago

Which of the following represents the subparticles for magnesium?

melomori [17]

The last one, 12p 12e 12n

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3 years ago

If you push twice as hard against a stationary brick wall, the amount of work you do

Alecsey [184]

Answer:

Zero

Explanation:

The work done on an object is given by:

$W=Fd cos \theta$

where

F is the force applied on the object

d is the displacement of the object

$\theta$ is the angle between the direction of the force and the displacement

In this problem, you are pushing again a stationary wall: this means that the walls does not move. As a result, the displacement is zero: d=0. Therefore, the work done is also zero: W=0.

8 0

3 years ago

A 500 kilogram roller coaster starts from rest at the top of an 80 meter hill.What was its speed at the bottom at the hill?

GarryVolchara [31]

m = mass of the roller coaster = 500 kg

h = height of the hill = 80 m

v = speed of the roller coaster at the bottom of the hill = ?

using conservation of energy

kinetic energy at the bottom of the hill = potential energy at the top of hill

(0.5) m v² = m g h

(0.5) v² = g h

inserting the values

(0.5) v² = (9.8) (80)

v = 39.6 m/s

hence the speed at the bottom comes out to be 39.6 m/s

3 0

3 years ago

What is friction and the types withe examples.​

What is friction and the types withe examples.