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3 years ago

How heart attacks and Strokes caused by cholesterol

2 answers:

8 0

With high cholesterol, you can develop fatty deposits in your blood vessels. Eventually, these deposits grow, making it difficult for enough blood to flow through your arteries. Sometimes, those deposits can break suddenly and form a clot that causes a heart attack or stroke.

skad [1K]3 years ago

8 0

Answer:

Cholesterol is a waxy substance found in your blood. Your body needs cholesterol to build healthy cells, but high levels of cholesterol can increase your risk of heart disease.

Explanation:

High cholesterol can cause a dangerous accumulation of cholesterol and other deposits on the walls of your arteries (atherosclerosis). These deposits (plaques) can reduce blood flow through your arteries, which can cause complications, such as:

Chest pain. If the arteries that supply your heart with blood (coronary arteries) are affected, you might have chest pain (angina) and other symptoms of coronary artery disease.

Heart attack. If plaques tear or rupture, a blood clot can form at the plaque-rupture site — blocking the flow of blood or breaking free and plugging an artery downstream. If blood flow to part of your heart stops, you'll have a heart attack.

Stroke. Similar to a heart attack, a stroke occurs when a blood clot blocks blood flow to part of your brain.

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Give me lil reasoning so I know your not lying for points

Natali5045456 [20]

Answer:

C. Tip had the lower pressure, it was 652.71mmHg

Explanation:

To answer this question you need to convert both values into a common unit so you can compare directly.

87kPa = 652.71 mmHg

4 0

3 years ago

The equilibrium constant Kc for the decomposition of phosgene, COCl2, is 4.63x10^-3 at 527 C. Calculate the equilibrium partial

Studentka2010 [4]

<u>Answer:</u> The partial pressure of the $CO,Cl_2\text{ and }COCl_2$ are 0.352 atm, 0.352 atm and 0.408 atm respectively.

<u>Explanation:</u>

We are given:

$K_c=4.63\times 10^{-3}$

$p_{COCl_2}=0.760atm$

Relation of $K_p$ with $K_c$ is given by the formula:

$K_p=K_c(RT)^{\Delta ng}$

Where,

$K_p$ = equilibrium constant in terms of partial pressure = ?

$K_c$ = equilibrium constant in terms of concentration = $4.63\times 10^{-3}$

R = Gas constant = $0.0821\text{ L atm }mol^{-1}K^{-1}$

T = temperature = $527^oC=527+273=800K$

$\Delta ng$ = change in number of moles of gas particles = $n_{products}-n_{reactants}=2-1=1$

Putting values in above equation, we get:

$K_p=4.63\times 10^{-3}\times (0.0821\times 800)^{1}\\\\K_p=0.304$

The chemical reaction for the decomposition of phosgene follows the equation:

$COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)$

At t = 0 0.760 0 0

At $t=t_{eq}$ 0.760-x x x

The expression for $K_p$ for the given reaction follows:

$K_p=\frac{p_{CO}\times p_{Cl_2}}{p_{COCl_2}}$

We are given:

$K_p=0.304\\p_{COCl_2}=0.760-x\\p_{CO}=x\\p_{Cl_2}=x$

Putting values in above equation, we get:

$0.304=\frac{x\times x}{0.760-x}\\\\x=0.352,-0.656$

Negative value of 'x' is neglected because partial pressure cannot be negative.

So, the partial pressure for the components at equilibrium are:

$p_{COCl_2}=0.760-0.352=0.408atm\\\\p_{CO}=0.352atm\\\\p_{Cl_2}=0.352atm$

Hence, the partial pressure of the $CO,Cl_2\text{ and }COCl_2$ are 0.352 atm, 0.352 atm and 0.408 atm respectively.

6 0

3 years ago

Which carboxylic acid can be combined with an alcohol to form the ester shown below?

Anna11 [10]

Answer:

CH₃CH₂CH₂COOH.

Explanation:

To know which option is correct, let us hydrolysed the given ester. This is illustrated in the attached photo.

Hydrolysis of ester involves breaking the ester bond by a water molecule to produce the corresponding alcohol and carboxylic acid.

From the reaction given in the attached photo, we can see that the carboxylic acid needed to produce the desired ester is butanoic acid, CH₃CH₂CH₂COOH.

7 0

3 years ago

Balance the reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1.

Ann [662]

2HCL + __ Zn --> ZnCl2 + H2

i think that's right, not exactly sure.

7 0

3 years ago

Read 2 more answers

Consider the reaction <img src="https://tex.z-dn.net/?f=N_2%20%2B%203%20H_2%20%5Crightarrow%202%20NH_3" id="TexFormula1" title="

sammy [17]

Answer: E

How much NH₃ can be produced from the reaction below:

N₂ + 3H₂ - 2NH₃

The stoichiometric ratio of the reactants = 1:3

Given

74.2g of N₂, and Molar mass = 14g/mole

Mole of N₂ = 74.2/14=5.3mols of N₂,

and 14mols of H₂

From this given values and comparing with the stoichiometric ratio, H₂ will be the limiting reagent while N₂ is the excess reactant.

i.e, for every 14mols of H₂, we need 4.67mols of N₂ to react with it to produce 9.33mols of NH₃ as shown (vice versa)

From this we have 9.33mols of NH₃ produced

Avogadro constant, we have n = no of particles = 6.022x10²³ molecules contained in every mole of an element.

For a 9.33mols of NH3, we have 9.33x6.022x10²³molecules in NH3

5.62x10²⁴molecules of NH₃

6 0

3 years ago

How heart attacks and Strokes caused by cholesterol​

How heart attacks and Strokes caused by cholesterol