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3 years ago

What has the lowest density out of solids, liquids, and gas?

Chemistry

2 answers:

qaws [65]3 years ago

8 0

Answer:

Explanation:

gas

Marysya12 [62]3 years ago

8 0

Answer:

gas

Explanation:

because the particals in gases are very far apart from each other

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What is the formula for triphosphorus tetrasulfide?

sladkih [1.3K]

Answer:

P3S4

Explanation:

hope this helps

3 0

2 years ago

When a H atom and a Cl atom react to form a HCl molecule,

seraphim [82]

...................?

3 0

3 years ago

Consider an ideal gas enclosed in a 1.00 L container at an internal pressure of 18.0 atm. Calculate the work, w , if the gas exp

Dominik [7]

Answer:

-32821.2 J (negative sign implies that work is done by the system)

Explanation:

The expression for the calculation of work done is shown below as:

$w=-P\times \Delta V$

Where, P is the pressure

$\Delta V$ is the change in volume

From the question,

$\Delta V$ = 18.0 - 1.00 L = 18.0 L

P = 18.0 atm

$w=-18.0\times18.0\ atmL$

Also, 1 atmL = 101.3 J

So,

$w=-18.0\times 18.0\times 101.3\ J=-32821.2\ J$ (negative sign implies that work is done by the system)

6 0

2 years ago

Rank these acids according to their expected pKa values.ClCH2COOHClCH2CH2COOHCH3CH2COOHCl2CHCOOHIn order of highest pka to lowes

Ilia_Sergeevich [38]

Answer:

CH₃CH₂CH₂COOH > CH₃CH₂COOH > ClCH₂CH₂COOH > ClCH₂COOH

Explanation:

Electron-withdrawing groups (EWGs) increase acidity by inductive removal of electrons from the carboxyl group.

Electron-donating groups (EDGs) decrease acidity by inductive donation of electrons to the carboxyl group.

The closer the substituent is to the carboxyl group, the greater is its effect.
The more substituents, the greater the effect.
The effect tails off rapidly and is almost zero after about three C-C bonds.

CH₃CH₂-CH₂COOH — EDG — weakest — pKₐ = 4.82

CH₃-CH₂COOH — reference — pKₐ = 4.75

ClCH₂-CH₂COOH — EWG on β-carbon— stronger — pKₐ = 4.00

ClCH₂COOH — EWG on α-carbon — strongest — pKₐ = 2.87

6 0

2 years ago

Read 2 more answers

A scientist wants to make a solution of tribasic sodium phosphate, Na3PO4, for a laboratory experiment. How many grams of Na3PO4

Anna71 [15]

Answer:

31.652g of Na3PO4

Explanation:

We'll begin by calculating the molarity of Na3PO4 solution. This can be achieved as shown below:

Na3PO4 will dessicate in solution as follow:

Na3PO4(aq) —> 3Na+(aq) + PO4³¯(aq)

From the balanced equation above,

1 mole of Na3PO4 produce 3 moles of sodium ion, Na+.

Therefore, xM Na3PO4 will produce 1.10M sodium ion, Na+ i.e

xM Na3PO4 = (1.10 x 1)/3

xM Na3PO4 = 0.367M

Therefore, the molarity of Na3PO4 is 0.367M.

Next, we shall determine the number of mole of Na3PO4 in the solution. This is illustrated below:

Molarity of Na3PO4 = 0.367M

Volume = 525mL = 525/1000 = 0.525L

Mole of Na3PO4 =..?

Molarity = mole /Volume

0.367 = mole /0.525

Cross multiply

Mole of Na3PO4 = 0.367 x 0.525

Mole of Na3PO4 = 0.193 mole.

Finally, we shall convert 0.193 mole of Na3PO4 to grams. This is illustrated below:

Molar mass of Na3PO4 = (23x3) + 31 + (16x4) = 164g/mol

Mole of Na3PO4 = 0.193 mole

Mass of Na3PO4 =.?

Mass = mole x molar mass

Mass of Na3PO4 = 0.193 x 164

Mass of Na3PO4 = 31.652g

Therefore, 31.652g of Na3PO4 is needed to prepare the solution.

6 0

2 years ago