Answer:
what are the options available?
Answer:
The correct answer is 0.004382 kW/K, the second law is a=satisfied and established because it is a positive value.
Explanation:
Solution
From the question given we recall that,
The transferred heat rate is = 2kW
A reservoir cold at = 300K
The next step is to find the rate at which the entropy of the two reservoirs changes is kW/K
Given that:
Δs = Q/T This is the entropy formula,
Thus
Δs₁ = 2/ 300 = 0.006667 kW/K
Δs₂ = 2 / 875 =0.002285
Therefore,
Δs = 0.006667 - 0.002285
= 0.004382 kW/K
Yes, the second law is satisfied, because it is seen as positive.
The net charge on the said dielectric is 0
1C = 6.25 * 10¹⁸ electrons; hence:
-12.5x10¹⁸ free electrons = (-12.5x10¹⁸ free electrons * (1C/ 6.25 * 10¹⁸ electrons))
-12.5x10¹⁸ free electrons = -2 C
A positively charged electric has a charge of 2 Coulombs, hence:
Q₁ = 2C
12.5x10¹⁸ free electrons are added to it, hence:
Q₂ = -2C
Hence the net charge on the said dielectric is 0
Find out more at: brainly.com/question/10464929
Answer:
F=1.47 KN
Explanation:
Given that
Diameter of plate = 25 cm
Height of pool h = 3 m
We know that force can be given as
F= P x A
P=ρ x g x h
Now by putting the values
P=1000 x 10 x 3
P= 30 KPa
F= 30 x 0.049 KN
F=1.47 KN
So the force on the plate will be 1.47 KN.
Answer:
The limits of the hole size are;
The maximum limit of the hole diameter 0.255
The minimum limit of the hole diameter = 0.245
Explanation:
Tolerance is a standardized form of language that can be used to define the intended 'tightness' or 'clearance' degree between mating parts in a mechanical assembly process and in metal joining processes such as welding and brazing processes
In tolerancing, the size used in the description of a part is known as the nominal size while allowable variation of the nominal size that will still allow the part to function properly is known as the tolerance
A tolerance given in the form ±P is known as bilateral tolerancing, with the value being added to or subtracted from the nominal size to get the maximum and minimum allowable limits of the dimensions of the nominal size
Therefore;
The given nominal dimension of the hole diameter = 0.250
The bilateral tolerance of the dimension, = ±0.005
Therefore;
The maximum limit of the diameter of the hole = 0.250 + 0.005 = 0.255
The minimum limit of the diameter of the hole = 0.250 - 0.005 = 0.245
