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3 years ago

why is nitrous oxide sedation especially useful for control of soft tissue discomfort during dental hygiene procedure

Chemistry

1 answer:

Stolb23 [73]3 years ago

7 0

Answer:

Because it has a quickly sedative effect and it has antimicrobial effect.

Explanation:

This gas is useful because is used to trait pain, reduce anxiety and promote relaxation, slow down the body reaction, so the dentist can use it to calm down the patients.

If the patient present some injuries, this gas can help in wound healing.

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Calculate the kilojoules needed to heat 231 g of gold from 18 ∘C to 195 ∘C.

LuckyWell [14K]

5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.

We have 231 g of gold at 18 °C and supply it with heat to increase its temperature to 195 °C. We can calculate the amount of heat required using the following expression.

$Q = c \times m \times \Delta T$

where,

Q: heat

c: specific heat capacity of gold (0.129 J/g.°C)

m: mass

ΔT: change in the temperature

$Q = \frac{0.129 J}{g.\° C} \times 231 g \times (195 \° C - 18 \° C) = 5.27 \times 10^{3} J = 5.27 kJ$

5.27 kJ of heat are required to heat 231 g of gold from 18 °C to 195 °C.

You can learn more about heating here: brainly.com/question/1105305

8 0

2 years ago

Hello people~

Paladinen [302]

Answer:

Polyester

Explanation:

Polyethylene terephthalate or shortly known as PET
its a clean and strong polyester
It is used in packaging

8 0

2 years ago

Read 2 more answers

Can someone help a dude out im stuck on this question

user100 [1]

Answer:

i think it is created

Explanation:

6 0

3 years ago

You are out on a hike, and you notice that the line of telephone wires you have been following along a slope is crooked. Two of

Tom [10]

Answer:

Explanation:

5 0

3 years ago

How many atoms are present in a sample of Potassium (K) weighing 33.49g?

madam [21]

Answer:

5.158 × 10²³ atoms K

General Formulas and Concepts:

Chemistry - Atomic Structure

Reading a Periodic Table
Using Dimensional Analysis
Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

Explanation:

Step 1: Define

33.49 g K

Step 2: Identify Conversions

Avogadro's Number

Molar Mass of K - 39.10 g/mol

Step 3: Convert

$33.49 \ g \ K(\frac{1 \ mol \ K}{39.10 \ g \ K} )(\frac{6.022 \cdot 10^{23} \ atoms \ K}{1 \ mol \ K} )$ = 5.15797 × 10²³ atoms K

Step 4: Check

We are given 4 sig figs. Follow sig figs and round.

5.15797 × 10²³ atoms K ≈ 5.158 × 10²³ atoms K

3 0

3 years ago