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tatuchka [14]
4 years ago
6

Identify the type of bonding molecular geometry and intermolecular forced experienced by the compounds hf and hbr which substanc

e would experience a stronger attraction between its molecules and why
Chemistry
1 answer:
Serhud [2]4 years ago
6 0
Both HF and HBr experience H-bond, dipole, and dispersion forces. These forces allow the compounds to have stronger bonds with each other. HF would experience a higher amount of attraction between its molecules. This is because fluorine is more electronegative than bromine.

Hope this helps!
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#11 plz help must need would appreciate it
mario62 [17]

Explanation:

325 g HgO

your answer

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7 0
3 years ago
How many valence electrons does a neutral atom of beryllium have
andrezito [222]

Answer:

A neutral Beryllium atom has two (2) valence electrons

Explanation:

<em>Beryllium, Be,</em> is a group 2 element on the periodic table. Its atomic number is 4.

Generally, atomic number equals number of electrons, which means a neutral Beryllium atom contains four (4) electrons: two (2)  in the inner shells and 2 in the outer shell (valence electrons), which can take part in a chemical reaction and participate in chemical bonding.

8 0
3 years ago
A beaker in your laboratory drawer has an inside diameter of 6.8 cm and a height of 8.9 cm. Using the equation V= arh, calculate
olga_2 [115]

Answer:

323.22 ml

Explanation:

Given that :

Diameter, d = 6.8cm

Height, h = 8.9cm

V = arh

Recall :

Volume, V = πr²h

Radius, r = diameter / 2 = 6.8 / 2 = 3.4cm

V = π * 3.4^2 * 8.9

V = 323.21961 cm³

Recall:

1ml = 1cm³

Hence,

323.21961 cm³ = 323.21961 ml

Volume = 323.22 ml

4 0
3 years ago
During the following chemical reaction, 46.3 grams of C3H6O react with 73.2 grams of O2
ra1l [238]

Answer:

a) O2 is the limiting reactant

b) 75.70 grams CO2 (theoretical yield)

c) There remains 12.81 grams of C3H6O

d) The actual yield CO2 is 34.29 grams

Explanation:

Step 1: Data given

Mass of C3H6O = 46.3 grams

Mass of O2 = 73.2 grams

Molar mass of C3H6O = 58.08 g/mol

Molar mass  of O2 = 32 g/mol

Step 2: The balanced equation

C3H6O + 4O2 → 3 CO2 + 3H2O

Step 3: Calculate moles C3H6O

Moles C3H6O = mass C3H6O / molar mass C3H6O

Moles C3H6O = 46.3 grams / 58.08 g/mol

Moles C3H6O = 0.793 moles

Step 4: Calculate moles O2

Moles O2 = 73.2 grams / 32 g/mol

Moles O2 = 2.29 moles

Step 5: Calculate limiting reactant

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed. (2.29 moles).

C3H6O is in excess. There will react 2.29/4 = 0.5725 moles C3H6O

There will remain 0.793 - 0.5725 = 0.2205 moles C3H6O

This is 0.2205 moles * 58.08 g/mol =<u> 12.81 grams</u>

Step 6:  Calculate moles of CO2

For 1 mol C3H6O we need 4 moles of O2 to produce 3 moles CO2 and 3 moles H2O

For 2.29 moles O2 we need 3/4 * 2.29 = 1.72 moles CO2

This is 1,72 moles * 44.01 g/mol = <u>75.70 grams CO2</u>

Step 7: Calculate actual yield

% yield = 45.3 % = 0.453 = (actual yield / theoretical yield)

actual yield = 0.453 * 75.70 = <u>34.29 grams</u>

3 0
3 years ago
Compare how mammals care for their young with the other groups of<br> animals.
slega [8]
Well, even though some baby mammals<span> are born different ways, they all drink milk that comes from </span>their<span> mothers' bodies. Baby pigs, dolphins, bats and elephants all drink milk! Because the </span>babies<span> rely on </span>their<span> mother's milk to live, the </span>mammal<span>mommies have to </span>care for their young<span>.</span>
4 0
3 years ago
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