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3 years ago

A circular disc has a diameter of 24 cm. What is the area of the disc?

Mathematics

1 answer:

agasfer [191]3 years ago

8 0

75.36 cm is the area of the disc

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What is the ratio of the volume of Cylinder A to the volume of Cylinder B?

erastovalidia [21]

Answer:

The ratio of volume of Cylinder A to the volume of Cylinder B is 18:25.

Step-by-step explanation:

Dimension of cylinder A,

Radius is 3 units and height is 4 units.

Dimension of cylinder B,

Radius is 5 units and height is 2 units.

The volume of a cylinder is given by :

$V=\pi r^2 h$

For cylinder A to B,

$\dfrac{V_A}{V_B}=(\dfrac{r_A}{r_B})^2\times \dfrac{h_A}{h_B}\\\\\dfrac{V_A}{V_B}=(\dfrac{3}{5})^2\times \dfrac{4}{2}\\\\\dfrac{V_A}{V_B}= \dfrac{18}{25}$

So, the ratio of volume of Cylinder A to the volume of Cylinder B is 18:25.

3 0

3 years ago

Triangle angle sum theorem<br> What is the value of z?

prisoha [69]

Answer:

z=3

Step-by-step explanation:

→32+76+24z=180[Sum of all sides of a triangle]

→108+24z=180

→24z=180-108

→z=72/24

→z=3

7 0

2 years ago

Read 2 more answers

A and B share the cost in a ratio of 3:2 . The cost is ?85; how much does A pay?

Katen [24]

Answer:

The amount of money A pays is $\$51$

Step-by-step explanation:

Let

x-----> amount of money A pays

y-----> amount of money B pays

we know that

$x+y=85$ ------> equation A

$\frac{x}{y}=\frac{3}{2}$

$y=\frac{2}{3}x$ ------> equation B

substitute equation B in equation A and solve for x

$x+(\frac{2}{3}x)=85$

$\frac{5}{3}x=85$

$x=85*3/5=\$51$

3 0

3 years ago

Fill in the missing portions of the function to rewrite g(x) = 3a^2 − 42a + 135 to reveal the zeros of the function. What are th

mariarad [96]

Answer:

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

Step-by-step explanation:

Given a second order polynomial expressed by the following equation:

$ax^{2} + bx + c, a\neq0$ .

This polynomial has roots $x_{1}, x_{2}$ such that $ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})$ , given by the following formulas:

$x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}$

$x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}$

$\bigtriangleup = b^{2} - 4ac$

In this question:

$g(x) = 3x^{2} - 42a + 135$

$a = 3, b = -42, c = 135$

$\bigtriangleup = (-42)^{2} - 4*3*135 = 144$

$x_{1} = \frac{-(-42) + \sqrt{144}}{2*3} = 9$

$x_{2} = \frac{-(42) - \sqrt{144}}{2*3} = 5$

g(x) = 3(x-9)(x-5)

Zeros: x = 9 and x = 5.

8 0

3 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

kobusy [5.1K]

Answer:

(1,1)

Step-by-step explanation:

I just finished the exam and got it correct, as you can see in the picture.

3 0

2 years ago