Answer: The concentrations of
at equilibrium is 0.023 M
Explanation:
Moles of
= 
Volume of solution = 1 L
Initial concentration of
= 
The given balanced equilibrium reaction is,

Initial conc. 0.14 M 0 M 0M
At eqm. conc. (0.14-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5Ctimes%20%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Now put all the given values in this expression, we get :

By solving the term 'x', we get :
x = 0.023 M
Thus, the concentrations of
at equilibrium is 0.023 M
1 mole K ------------- 6.02x10²³ atoms
1.83 moles K ------ ?? atoms
1.83 x (6.02x10²³) / 1 =
1.101x10²⁴ atoms of K
hope this helps!
Answer:
Its B
Explanation:
Products <=> reactants; products can go back to reactant and reactants can form products, depending on the equilibrium position.
The equilibrium position, if it is on the left, and much of the product is formed. If the equilibrium position is not the right, then its the vice versa The equilibrium position is determined by ;
- <em><u>Temperature</u></em>
If the reaction is endothermic, it will be favoured by increase in temperature and equilibrium position will shift to the right ( reactants )
If the reaction is exothermic, its the vice versa
<em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u>E</u></em><em><u>:</u></em><em><u> </u></em>Only temperature affects the equilibrium position