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konstantin123 [22]
3 years ago
5

A runner stood at the 100-meter mark on a track. When the timer started, the runner sprinted north to the 200-meter mark. It too

k the runner 25 seconds to get to the 200-meter mark. What was the average velocity of the runner while he was sprinting?
Chemistry
2 answers:
Olegator [25]3 years ago
3 0

Answer:

8 m/s north

Explanation:

Eddi Din [679]3 years ago
3 0

The average velocity of the runner while he was sprinting is 4 m/s.

<u>Solution:</u>

Given the runner sprinted from 100m mark to 200m mark, which means the displacement of the runner is 200-100=100m.

The time taken to travel this 100 distance is 25 seconds.

\text { Average velocity }=\frac{\text { displacement }}{\text { time }}

\Rightarrow \frac{100}{25}=4 \mathrm{m} / \mathrm{sec}

Note: The direction of the average velocity is in the direction of the displacement

Therefore, average velocity = 4 m/s

Average velocity:

Average velocity of an object can be defined as the displacement divided by the time taken by the object.

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Amorphous solids is one that do not have a fixed melting points but melt over a wide range of temperature due to the irregular shape hence its name. Contrariwise crystalline solids, have a fixed and sharp melting point.

This comes in handy to solve the riddle. We can characterise the pair with the melting point property.

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<h3>What is an ore?</h3>

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i hope this helps :)

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