Answer:
Dipole-dipole forces
Explanation:
A polar compound is that compound which contains atoms that have a difference in charges i.e electrostatic attraction occurs between its constituent atoms. Polar molecules are attracted to other polar molecules with opposite charges and her held together with the aid of certain forces
The attractive force between the negative part of a polar molecule (-) and the positive part of another polar molecule (+) is called DIPOLE-DIPOLE FORCES. This dipole-dipole force gets stronger with an increasing polarity of the molecules involved.
The iupac name of the compound will be hex-3-yne or 3-hexyne. By marking number of carbon in the given compound, it was found that triple bond comes at third position and there are total 6 carbon in the compound. So it will have Hex as a prefix and as it contains triple bond so it will have yne as a suffix and as the triple bond is at third position, so it will be hex-3-yne or 3-hexyne.
The structure of alkene is given below in the image.
Alkenes are described as both branched or unbranched hydrocarbons that possess at least one carbon-carbon double bond (CC) and feature a popular system of CnH2n [1].
Alkanes are organic compounds that encompass single-bonded carbon and hydrogen atoms. The formulation for Alkanes is CnH2n+2, subdivided into 3 companies – chain alkanes, cycloalkanes, and branched alkanes.
The geometry around each carbon atom is based totally on a trigonal planar shape, due to the fact, that each carbon has three electrons around it. This must make the angle of each bond one hundred twenty.
Learn more about Alkanes here: brainly.com/question/17040500
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Answer:
Explanation:
Use the gas equation: PV=nRT
P=pressure
V=Volume
R= gas constant of around 8.31 J/K/mol
T=temperature
n= number of moles
To find n, Rearrange:
n=PV/RT
102kPa= 102,000 kilo pascals which standard form is 102 x 10^3
Convert Celsius to kelvin, which you just add 273.15. So:
37+273.15=310.15 K round to a whole number is 310 K
Sub in all numbers to calculate the mol
n= 102 x 10^3 x 2.20 x 10^3/ 8.31 x 310 (cross out 10^3 as this will make a big number)
n=102 x 2.2/8.31 x 310 =0.087 mol
We know 1 g=29 moles
Multiply 29 moles with 0.087 to find the grams
29*0.087=2.523, which to one d.p is 2.5 g
Hence, the child's lung will hold 2.5 g of air.
Hope this helps you :)
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