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3 years ago

What will the volume of 254 cm3 of gas be at STP if its original temperature is 72.6° C?

Chemistry

1 answer:

juin [17]3 years ago

3 0

Answer:

200.6cm³

Explanation:

Using Charles law equation as follows:

V1/T1 = V2/T2

Where;

V1 = initial volume (cm³)

V2 = final volume (cm³)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the question;

initial volume (V1) = 254cm³

final volume (V2) = ?

Initial temperature (T1) = 72.6°C = 72.6 + 273 = 345.6K

Final temperature (T2) = 273K

V1/T1 = V2/T2

254/345.6 = V2/273

Cross multiply

345.6 × V2 = 273 × 254

345.6V2 = 69342

V2 = 69342 ÷ 345.6

V2 = 200.6cm³

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4 years ago

A sample of a gas (1.50 mol) is contained in a 15.0 l cylinder. the temperature is increased from 100 °c to 150 °c. what is the

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Given:

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Volume of cylinder, V = 15.0 L

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Final temperature, T2 = 150 C = (150+273)K = 423 K

To determine:

The pressure ratio

Explanation:

Based on ideal gas law:

PV = nRT

P= pressure; V = volume; n = moles; R = gas constant and T = temperature

under constant n and V we have:

P/T = constant

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where P1 and P2 are the initial and final pressures respectively

substituting for T1 and T2 we get:

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Thus, the ratio of P2/P1 = 1.13

Ans: The pressure ratio is 1.13

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