In a synthesis experiment you obtain a sample of product on which you do a melting point determination and find a melting point
1 answer:
Answer:
The melting point determination may need improvement- it may not have been done properly, and make sure it was repeated at least once.
Explanation:
Given that we know the actual melting point of pure acetylsalicyclic acid to be 135°, it follows that the process followed to obtain the melting point range of 114 to 125 degrees Celsius must be inaccurate.
Therefore, we can conclude that, the melting point determination may need improvement. It may not have been done properly, and we must make sure it is repeated at least once.
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<u>Answer :</u>
Part 13:
The balanced chemical reaction will be:
Part 14:
The balanced chemical reaction will be:
Part 15:
The balanced chemical reaction will be:
<u>Explanation :</u>
Balanced chemical reaction : It is defined as the reaction in which an individual element of an atom present on reactant side must be equal to product side.
Part 13:
The balanced chemical reaction will be:
Part 14:
The balanced chemical reaction will be:
Part 15:
The balanced chemical reaction will be:
<u>Answer:</u> The percent yield of the reaction is 32.34 %
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For benzoic acid:</u>
Given mass of benzoic acid = 3.6 g
Molar mass of benzoic acid = 122.12 g/mol
Putting values in equation 1, we get:
The chemical equation for the reaction of benzoic acid and methanol is:
By Stoichiometry of the reaction
1 mole of benzoic acid produces 1 mole of methyl benzoate
So, 0.0295 moles of benzoic acid will produce = moles of methyl benzoate
- Now, calculating the mass of methyl benzoate from equation 1, we get:
Molar mass of methyl benzoate = 136.15 g/mol
Moles of methyl benzoate = 0.0295 moles
Putting values in equation 1, we get:
- To calculate the percentage yield of methyl benzoate, we use the equation:
Experimental yield of methyl benzoate = 1.3 g
Theoretical yield of methyl benzoate = 4.02 g
Putting values in above equation, we get:
Hence, the percent yield of the reaction is 32.34 %