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yawa3891 [41]
3 years ago
8

The four tastes are: bitter sour fishy salty fruity sweet

Chemistry
1 answer:
Minchanka [31]3 years ago
7 0
Bitter, sour, salty, sweet.
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What is the iupac name of this structure?
alexgriva [62]

Answer:

3–ethyl–4–methylhexane.

Explanation:

To name the above compound, do the following:

1. Determine the functional group of the compound.

2. Locate the longest continuous carbon chain. This gives the parent name of the compound.

3. Identify the substituent group attached to the compound.

4. Give the substituent the lowest possible count.

5. Combine the above to name the compound.

Now, we shall name the compound given in the question above as follow:

1. The compound contains only single bond. Therefore, the compound belong to the alkane family.

2. The longest continuous carbon chain is 6 i.e hexane.

3. The substituent group attached are:

i. Methyl, CH3.

ii. Ethyl, CH2CH3.

4. we shall name the substituents alphabetically i.e ethly will come before methyl. Therefore,

Ethyl is located at carbon 3.

Methy is located at carbon 4.

5. Therefore, the name of the compound is:

3–ethyl–4–methylhexane.

5 0
2 years ago
27 Which energy conversion must occur in an operating electrolytic cell?
Vitek1552 [10]
<u> electrical energy to chemical energy</u>
5 0
3 years ago
What is the orbital or electronic geometry of a molecule with 0 nonbonding electron pairs and 2 bonding electron pairs?
disa [49]
Linear is the answer
3 0
3 years ago
Which substance has Hf defined as 0 kJ/mol? H2O (s) Ne (l) O2 (g) CO2 (g)
vlabodo [156]

Answer:

O₂ (g).

Explanation:

  • All elements that found in nature has heat of formation (Hf) equal 0 J/mol.
  • So, the substance that  has heat of formation (Hf) equal 0 J/mol is O₂ (g).
  • H₂O is formed from the reaction of hydrogen and oxygen and has Hf, Also, the solidification of H₂O (s) from H₂O (l) has (Hf).
  • Although, Ne (g) is found in nature and has no Hf, the liquification to form Ne (l) has heat of formation (Hf).
  • CO₂ (g) is formed from the reaction between carbon and oxygen and so has heat of formation (Hf).
8 0
3 years ago
Read 2 more answers
Calculate the p value of each ion indicated:
Nataliya [291]
27/208  = normality

12 x 10^-2 approx  = normality

nw Ka = 14.3 x 10^-3

pKa = 3 - log 14

now, after getting the pKa put it in formula  :
pH = pKa + log concn of ion/concn of salt and you'll get it

hope this helps
8 0
2 years ago
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