SrSo4 = Sr(2+) + SO4(2-)
Let’s say that the initial concentration of SrSo4 was 1. ( or we have 1 mole of this reagent).
When The reaction occurs part of SrSo4is dissociated. And we get X mole Sr(2+) and So4(2-).
Ksp=[Sr(2+)]*[SO4(2-)]
X^2=3.2*10^-7
X=5.6*10^-4
I believe your answer would be the first one
hope this helps
Answer:
Molar mass = 151.9 g/mol
Explanation:
The molar mass of a compound is obtained by adding u the individual atomic masses in the compound. The unit is g/mol.
In FeSO4, we have one Fe, one S and 4 O.
The atomic masses are given as follows;
Fe = 55.845 u
S = 32.065 u
O = 15.999 u
Molar mass = ( 1 * Fe) + (1 * S) + (4 * O)
Molar mass = (1 * 55.854 ) + ( 1 * 32.065) + (4 * 15.999)
Molar mass = 151.915 g/mol
In four significant figures;
Molar mass = 151.9 g/mol
