Answer:
The volume of sludge after filtration is 0.914 m
Explanation:
Solution
Given that:
We have to find the Volume of sludge after filtration
Now,
The Sludge concentration is = 32%,
The sludge volume = 100 m,
The sludge concentration after filtration = 35%
Then,
The mass balance equation is stated below
Cin∀in = Cout∀out
Now,
We Solve for ∀out
∀out =Cin∀in/Cout
By substituting the values
∀out = (0.32)(100 m)/(0.35) = 0.914 m
Answer:
2376 vph
Explanation:
Given data
free flow speed ( Vf ) = 45 mph
Jam density = 25 ft per vehicle
flow rate = 1950 vph
first we calculate the Jam density in vehicle /mile
= 5280 / 25 = 211.2 vehicle/mile
where ; 1 mile = 5280 feet
The maximum flow can be calculated using Greenshield method
q = ( Vf * jam density ) / 4 = ( 45 * 211.2 ) / 4
= 2376 vph
Answer:
F = 2,355 10⁵ N
Explanation:
The pressure is distributed throughout the sphere with the same value and is defined by
P = F / A
F = P A
Therefore, on each bolt there is an internal force and external force
∑ F = F_int - F_ext
∑ F = P_int A - P_atm A
F = A (P_int - P_atm)
P_int = 300 10³ + P_atm
F = A 300 10³
The area of the sphere layer is
A = π r² = π/ 4 d²
A = π / 4 1²
A = 0.785 m2
F = 0.785 (300 10³)
F = 2,355 10⁵ N
Answer:
a) 254.6 GPa
b) 140.86 GPa
Explanation:
a) Considering the expression of rule of mixtures for upper-bound and calculating the modulus of elasticity for upper bound;
Ec(u) = EmVm + EpVp
To calculate the volume fraction of matrix, 0.63 is substituted for Vp in the equation below,
Vm + Vp = 1
Vm = 1 - 0.63
Vm = 0.37
In the first equation,
Where
Em = 68 GPa, Ep = 380 GPa, Vm = 0.37 and Vp = 0.63,
The modulus of elasticity upper-bound is,
Ec(u) = EmVm + EpVp
Ec(u) = (68 x 0.37) + (380 x 0.63)
Ec(u) = 254.6 GPa.
b) Considering the express of rule of mixtures for lower bound;
Ec(l) = (EmEp)/(VmEp + VpEm)
Substituting values into the equation,
Ec(l) = (68 x 380)/(0.37 x 380) + (0.63 x 68)
Ec(l) = 25840/183.44
Ec(l) = 140.86 GPa
