Answer:
<em>181 °C</em>
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Explanation:
Initial pressure 
= 100 kPa
Initial temperature 
= 30 °C = 30 + 273 K = 303 K
Final pressure 
= 1200 kPa
Final temperature 
= ?
n = 1.2
For a polytropic process, we use the relationship
(/ ) = (/)^γ
where γ = (n-1)/n
γ = (1.2-1)/1.2 = 0.1667
substituting into the equation, we have
(/303) = (1200/100)^0.1667
/303 = 12^0.1667
/303 = 1.513
= 300 x 1.513 = 453.9 K
==> 453.9 - 273 = 180.9 ≅ <em>181 °C</em>
Answer:
When the renewal period comes around (with respect to the license expiry date).
Explanation:
Answer:
2062 lbm/h
Explanation:
The air will lose heat and the oil will gain heat.
These heats will be equal in magnitude.
qo = -qa
They will be of different signs because one is entering iits system and the other is exiting.
The heat exchanged by oil is:
qo = Gp * Cpo * (tof - toi)
The heat exchanged by air is:
qa = Ga * Cpa * (taf - tai)
The specific heat capacity of air at constant pressure is:
Cpa = 0.24 BTU/(lbm*F)
Therefore:
Gp * Cpo * (tof - toi) = Ga * Cpa * (taf - tai)
Ga = (Gp * Cpo * (tof - toi)) / (Cpa * (taf - tai))
Ga = (2200 * 0.45 * (150 - 100)) / (0.24 * (300 - 200)) = 2062 lbm/h
