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pychu [463]
3 years ago
11

The specific gravity of a substance that has mass of 10 kg and occupies a volume of 0.02 m^3 is a) 0.5 b) 1.5 c) 2.5 d) 3.5 e) n

one of these
Engineering
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

Specific gravity is 0.5 so option (a) is correct option

Explanation:

We have given mass of substance m =10 kg

Volume V=0.02m^3

Density of substance is given by Density\ d=\frac{mass}{volume}=\frac{10}{0.02}=500kg/m^3

Specific gravity is given by specific\ gravity=\frac{density\ of\ substance}{density\ f\ water}=\frac{500}{1000}=0.5

So option (a) is correct option

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You are driving on a roadway with multiple lanes of travel in the same direction, and are approaching an emergency vehicle parke
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Read 2 more answers
a circular pile, 19 m long is driven into a homogeneous sand layer. The piles width is 0.5 m. The standard penetration resistanc
Elena L [17]

Answer:

Point force (Qp) = 704 kn/m²

Explanation:

Given:

length = 19 m

Width = 0.5 m

fs = 4

Vicinity of the pile = 25

Find:

Point force (Qp)

Computation:

Point force (Qp) = fs²(l+v)

Point force (Qp) = 4²(25+19)

Point force (Qp) = 16(44)

Point force (Qp) = 704 kn/m²

5 0
2 years ago
Assume you are an observer standing at a point along a three-lane roadway. All vehicles in lane 1 are traveling at 30 mi/h, all
garik1379 [7]

Answer:

Explanation:

Given data;

  • In line 1, v1 = 30mi/hr
  • in line 2, v2 = 45mi/hr
  • in line 3, v3 = 60mi/hr
  • therefore time mean speed = v1 + v2 + v3 /n
  • = VT = 45mi/hr

  • space mean speed ; Vs
  • harmonic mean = 1/V = 1/v1 + 1/v2 + 1/v3
  • V = 13.85mi/hr
  • Hence Vs = V x n = 3 x 13.85 = 41.55mi/hr
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