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pychu [463]
3 years ago
11

The specific gravity of a substance that has mass of 10 kg and occupies a volume of 0.02 m^3 is a) 0.5 b) 1.5 c) 2.5 d) 3.5 e) n

one of these
Engineering
1 answer:
zhuklara [117]3 years ago
5 0

Answer:

Specific gravity is 0.5 so option (a) is correct option

Explanation:

We have given mass of substance m =10 kg

Volume V=0.02m^3

Density of substance is given by Density\ d=\frac{mass}{volume}=\frac{10}{0.02}=500kg/m^3

Specific gravity is given by specific\ gravity=\frac{density\ of\ substance}{density\ f\ water}=\frac{500}{1000}=0.5

So option (a) is correct option

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9) A construction company employs 2 sales engineers. Engineer 1 does the work in estimating cost for 70% of jobs bid by the comp
Irina18 [472]

The probability that the error occurred when Engineer 2 made the mistake is 0.462 on the other hand the probability that the error occurred when the engineer 1 made the mistake is 0.538

Explanation:

Let E_{1} denote the event that the 1st  engineer  does the work.so we write

P(E)_{1}=0.7

Let E_{2} denote the event that the 2nd engineer  does the work .So we write

P(E)_{2}=0.3

Let O denote the event during which the error occurred .so we write

P(O/E_{1} )=0.02(GIVEN)

P(O/E_{2} )=0.04(GIVEN)

  • The probability that the error occurred when the first engineer performed the work is P(E_{1} /O)
  • The probability that the error occurred when the first engineer performed the work is P(E_{2} /O)

Now we need to find when did the error in the work occur so we will compare the probability of the work done by <u>engineer 1 </u>and <u>engineer 2 </u>

<u></u>

<u>lets find the Probability of the Engineer 1</u>

<u>Using Bayes theorem,we get</u>

<u></u>

<u></u>P(E_{1} /O) =0.02*0.7/0.02*0.7+0.04*0.3 = 0.014/0.026=0.538

<u>lets find the Probability of the Engineer 2</u>

<u></u>P(E_{2} /O) =0.04*0.3/0.02*0.7+0.04*0.3=0.012/0.026=0.462

Since ,0.462<0.538 so it is more prominent that the Engineer 1 did the work when the error occurred

3 0
3 years ago
Hydrogen gas (density = 1.165 kg/m^3 ) is stored at 25°C in a permeable cylindrical container which has an outer diameter of 0.2
AVprozaik [17]

Answer:

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Explanation:

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3 years ago
Two well-known NP-complete problems are 3-SAT and TSP, the traveling salesman problem. The 2-SAT problem is a SAT variant in whi
Hitman42 [59]

3-SAT ≤p TSP

If P ¹ NP, then no NP-complete problem can be solved in polynomial time.

both the statements are true.

<u>Explanation:</u>

  • 3-SAT ≤p TSP due to any  complete problem of NP to other problem by exits of reductions.
  • If P ¹ NP, then 3-SAT ≤p 2-SAT are the polynomial time algorithm are not for 3-SAT. In P, 2-SAT is found, 3- SAT polynomial time algorithm implies the exit of reductions. 3 SAT does not have polynomial time algorithm when P≠NP.
  • If P ¹ NP, then no NP-complete problem can be solved in polynomial time. because for the NP complete problem individually gets the polynomial time algorithm for the others. It may be in P for all the problems, the implication of latter is P≠NP.
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Answer:

Explanation:

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