1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
DaniilM [7]
3 years ago
13

WHAT IS THE MOST POWERFUL PART IN A CAR

Engineering
2 answers:
STatiana [176]3 years ago
7 0
I think it would be the cage
DiKsa [7]3 years ago
6 0
The cage because it protects us
You might be interested in
1. True/False The Pressure Relief valve maintains the minimum pressure in the hydraulic circuit​
elena55 [62]
Yeah it’s true. Good luck!!
3 0
3 years ago
14. A large car fire presents the possibility of
dexar [7]

Answer:

Both of the above

Explanation:

5 0
2 years ago
Read 2 more answers
Only respond if your the person im talkin to
bagirrra123 [75]

Answer: um wuh anyways thxs for the points!

Explanation: ....:/

5 0
3 years ago
Plzzzz helppp design process in order
MA_775_DIABLO [31]

Answer:

generate

define

present

evaluate

develop

construct and test

7 0
2 years ago
In an orthogonal cutting operation, the tool has a rake angle = 12°. The chip thickness before the cut = 0.32 mm and the cut yie
Snezhnost [94]

Answer:

The shear plane angle and shear strain are 28.21° and 2.155 respectively.

Explanation:

(a)

Orthogonal cutting is the cutting process in which cutting direction or cutting velocity is perpendicular to the cutting edge of the part surface.  

Given:  

Rake angle is 12°.  

Chip thickness before cut is 0.32 mm.

Chip thickness is 0.65 mm.  

Calculation:  

Step1  

Chip reduction ratio is calculated as follows:  

r=\frac{t}{t_{c}}

r=\frac{0.32}{0.65}

r = 0.4923

Step2  

Shear angle is calculated as follows:  

tan\phi=\frac{rcos\alpha}{1-rsin\alpha}

Here, \phi is shear plane angle, r is chip reduction ratio and \alpha is rake angle.  

Substitute all the values in the above equation as follows:  

tan\phi=\frac{rcos\alpha}{1-rsin\alpha}

tan\phi=\frac{0.4923cos12^{\circ}}{1-0.4923sin12^{\circ}}

tan\phi=\frac{0.48155}{0.8976}

\phi=28.21^{\circ}

Thus, the shear plane angle is 28.21°.

(b)

Step3

Shears train is calculated as follows:

\gamma=cot\phi+tan(\phi-\alpha)

\gamma=cot28.21^{\circ}+tan(28.21^{\circ}-12^{\circ})\gamma = 2.155.

Thus, the shear strain rate is 2.155.

6 0
3 years ago
Other questions:
  • Find the mathematical equation for SF distribution and BM diagram for the beam shown in figure 1.​
    10·1 answer
  • A Si sample contains 1016 cm-3 In acceptor atoms and a certain number of shallow donors, the In acceptor level is 0.16 eV above
    5·2 answers
  • If the Zener diode is connected<br>wrong polarity the voltage<br>across the load is?​
    11·1 answer
  • The Acme tool is aligned to the work with: A. A square B. The eye C. An Acme tool gage D. A center gage
    14·1 answer
  • Cho biết tác dụng chung của các hệ giằng khung ngang nhà công nghiệp nhẹ 1 tầng 1 nhịp.
    13·1 answer
  • What is the purpose of making a jello pool
    6·1 answer
  • Respond with TRUE if the symbol of the valve shown belows
    5·1 answer
  • 6.) ___________ is a disadvantage of local storage since it can be very expensive.
    5·1 answer
  • Which step in the engineering design process does not come before building a<br> prototype?
    12·1 answer
  • How high of a column of sae 30 oil would be required to give the same pressure as 700 mm hg?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!