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3 years ago

Pleasseee help!! Got STUCK FOR A WHILE!! How does this equation help you to understand acids and bases: H+(aq) + OH-(aq)H2O(aq)?

Chemistry

1 answer:

Gekata [30.6K]3 years ago

7 0

Answer:

Odd answer choices, but I would put "It shows you that water is a reversible reaction, which contains hydrogen and hydroxide reactions."

Explanation:

The first choice is weird, although water can be written as HOH that doesn't help you understand acids and bases.

The third choice doesn't do that either, and there are more ways for water to be formed than that.

The second choice helps you understand acids and bases, specifically, in water's self-ionization process. It also shows you that it is neutral because it is formed from Hydrogen, which is usually present in acids, and a Hydroxide group, which is usually present in bases.

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Explanation:

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3 years ago

Cutting a piece of paper in half proves that solids have no definite shape.<br><br> True or False?

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3 years ago

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Answer:

A pH of 7 is neutral.A pH of less than 7 is acidic.

Explanation:

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3 years ago

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Anastaziya [24]

Answer:

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3 years ago

A certain radioactive isotope decays at a rate of 0.2% annually. Determine the half-life of this isotope, to the nearest year

pychu [463]

Answer:

The half-life of the radioactive isotope is 346 years.

Explanation:

The decay rate of the isotope is modelled after the following first-order linear ordinary differential equation:

$\frac{dm}{dt} = -\frac{m}{\tau}$

Where:

$m$ - Current isotope mass, measured in kilograms.

$t$ - Time, measured in years.

$\tau$ - Time constant, measured in years.

The solution of this differential equation is:

$m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }$

Where $m_{o}$ is the initial mass of the isotope. It is known that radioactive isotope decays at a yearly rate of 0.2 % annually, then, the following relationship is obtained: