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Thepotemich [5.8K]

3 years ago

5

Professor Stats has 40 students in her statistics class. 24 of the students are male. If she randomly selects 6 of her students

at random, without replacement, the probability of selecting 4 men in the sample is

1 answer:

Aleonysh [2.5K]3 years ago

7 0

Answer:

the answer is 332

Step-by-step explanation:

quizlet

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Because of the increasing nuisance of spam e-mail messages, many start-up companies have emerged to develop e-mail filters. One

BaLLatris [955]

Answer:

B. 95% of spam is blocked.

4 0

3 years ago

Anna [14]

Answer:

a = 6

Step-by-step explanation:

-6(2 + a) = -48

it is basically 2 steps

Divide by -6 first

(2 + a) = -48 / -6

2 + a = 8

minus the 2

a =6

5 0

3 years ago

Read 2 more answers

Hey! can u help me with this?! 6 divided by 3/5 in fraction form!?!?!!?

frutty [35]

Answer:

10/1

Step-by-step explanation:

You do

6÷ 3/5

Flip the 3/5 then multiply

6 ° 5/3

Reduce the numbers with the greatest common factor 3

So 2•5

And that's 10

4 0

3 years ago

Read 2 more answers

Un cono ha l'area laterale di 255 pigreco cm^2, l'apotema di 17 cm e pesa 900 pigreco g. Calcola il peso specifico del materiale

valkas [14]

Answer:

The specific weight is $1.5\frac{g}{cm^{3}}$

Step-by-step explanation:

The question in English

A cone has a lateral area of 255 pi cm^2, an apothem of 17 cm and weighs 900 pi g. It calculates the specific weight of the material of which it is composed

step 1

Find the radius of the cone

we know that

The lateral area of a cone is equal to

$LA=\pi rl$

we have

$LA=255\pi\ cm^{2}$

$l=17\ cm$

substitute the values

$255\pi=\pi r(17)$

Simplify

$255=r(17)$

$r=255/(17)=15\ cm$

step 2

Find the height of the cone

Applying the Pythagoras Theorem

$l^{2} =r^{2} +h^{2}$

substitute the values and solve for h

$17^{2} =15^{2} +h^{2}$

$h^{2}=17^{2}-15^{2}$

$h^{2}=64$

$h=8\ cm$

step 3

Find the volume of the cone

The volume of the cone is equal to

$V=\frac{1}{3}\pi r^{2}h$

substitute the values

$V=\frac{1}{3}\pi (15)^{2}(8)$

$V=600\pi\ cm^{3}$

step 4

Find the specific weight

Divide the mass by the volume

$\frac{900\pi }{600\pi}=1.5\frac{g}{cm^{3}}$

4 0

3 years ago

The fountain is made up of two semicircles and a quarter circle. Find the perimeter and the area of the fountain. Round the peri

Andrej [43]

FOUND THE COMPLETE QUESTION IN ANOTHER SOURCE.ATTACHED IMAGE.
For this case what we have is the following:
For the two semicircles we can model it as a complete circle.
We have to then:

Perimeter:
P = 2 * pi * r
or
P = pi * d
Where,
r = radius
d = diameter
Therefore the perimeter is:
P = 10 * pi
For the largest circle we have:
radius = 10
Perimeter:
P '= 2pi10
P '= 20pi
1/4 since 1/4 circle:
P '' = 20pi / 4 = 5pi
Then, the total perimeter of the source is:
Pt = P + P '' = 10pi + 5pi = 15pi
Pt = 15 * (3.141592)
Pt = 47.1239
round
Pt = 47.1 ft

Area:
The total area will be:
A = A (two semicircles) + A (quarter big circle)
A = (pi / 4) * (d ^ 2) + (1/4) * pi * r ^ 2
A = (pi / 4) * ((10) ^ 2) + (1/4) * pi * (5) ^ 2
A = 98.17477042 feet ^ 2
Round:
A = 98.2 feet ^ 2

Answer:
Perimeter of the source:
Pt = 47.1 ft
Area of the source:
A = 98.2 feet ^ 2

5 0

3 years ago