The vertical movement of the projectile is described by:
y = H - gt² / 2
When the cannonball is on the ground, y= 0 so:
0 = H - gt² /2
Solving for t:
The horizontally movement of the projectile is described by:
x = v₀t
Solving for v₀:
v₀ = x/t
v₀ = 175 m / 2.8 s
v₀ = 61.5 m/s
Suppose that the cyclist begins his journey from the rest from the top of a wedge with a slope of a degree above the horizontal.
At point A (where it starts its journey), the energy is:
Ea = m * g * h
In other words, energy is only potential.
At point B (located at the bottom of the wedge), the energy is:
Eb = (1/2) * (m) * (v ^ 2)
In other words, the energy is only kinetic.
For energy conservation we have:
Ea = Eb
That is, we have that all potential energy is transformed into kinetic energy.
Which means that the cyclist has less kinetic energy at point A because that's where he has more potential energy.
answer:
the cyclist has less kinetic energy at point A because that's where he has more potential energy.
For this, you need the v-squared equation, which is v(final)² = v(initial)² + 2aΔx
The averate acceleration is thus a = (v(final)² - v(initial)²) / 2Δx = (20² - 15²) / 2(50) = 175 / 100 = 1.75 m/s²
So the average acceleration is 1.75 m/s²
<h3>
Answer:</h3>
1.3 Amps
<h3>
Explanation:</h3>
<u>We are given;</u>
A circuit with resistors, R1 and R2
R1 = 7 Ω
R2 = 11 Ω
Voltage = 24 V
We are required to calculate the current in the circuit.
<h3>Step 1: We need to find the effective resistance.</h3>
When resistors are arranged in series, the effective resistance is calculated by;
Rt = R₁ + R₂ + R₃ + ..........Rₙ
Therefore;
Total resistance = 7 + 11
= 18 Ω
<h3>Step 2: Calculate the current in the circuit</h3>
From the ohm's law;
V = IR
Rearranging the formula;
I = V/R
Thus;
I = 24 V ÷ 18 Ω
= 1.333 Amps
= 1.3 Amps
Thus, the current in the circuit is 1.3 Amps
Where r is the radius of balloon.
Here mass of woman = 68 kg
Mass of air displaced by a balloon with volume V = 1.29*V
Mass of helium inside balloon = 0.178*V
Total mass to be lifted by balloon = 68 +0.178*V
Buoyant force = 1.29V-0.178V=1.112V
So we have 1.112 V = 68+ 0.178*V
0.934 V = 68
V = 72.81 
\frac{4}{3} \pi r^{3}[/tex]= 72.81
r = 2.59 m
So radius of helium balloon = 2.59 m
