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3 years ago

In the context of depth perception, which of the following is a monocular cue?

1 answer:

8 0

Hello there.

<span>In the context of depth perception, which of the following is a monocular cue?

</span><span>(C) Convergence
</span>

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the volume of a water tank is 5m×4m×2m. If the tank is half filled with water. calculate the pressure exerted at the bottom of t

Natali5045456 [20]

Answer:

10⁴ Pa

Explanation:

Volume = 5m * 4m * 2m

When the tank is half filled ,

Volume = 5m * 4m * 1m = 20m³

Also we know that ,

Density of water = 10³ kg/ m³

$\longrightarrow$ Density = Mass/Volume

$\longrightarrow$ 10³ kg/m³ = m/20m³

$\longrightarrow$ m = 2 * 10⁴ kg

So that ,

$\longrightarrow$ Weight = mg

$\longrightarrow$ F = 2*10⁴ × 10 N

$\longrightarrow$ F = 2 * 10⁵ N

And ,

$\longrightarrow$ Pressure = Force/Area

$\longrightarrow$ P = 2 *10⁵/ 5 * 4 Pa

$\longrightarrow$ P = 10⁴ Pa

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3 years ago

A massless spring with force constant ????=200N/m hangs from the ceiling. A 2.0-kg block is attached to the free end of the spri

Makovka662 [10]

Answer:

-0.4454 Joules

Explanation:

m = Mass of block = 2 kg

h = Height of extension = 17 cm = x

g = Acceleration due to gravity = 9.81 m/s²

Potential energy of the spring

$P=mgh\\\Rightarrow P=2\times 9.81\times 0.17\\\Rightarrow P=3.3354\ J$

The kinetic energy of the spring

$K=\frac{1}{2}mx^2\\\Rightarrow K=\frac{1}{2}\times 200\times 0.17^2\\\Rightarrow K=2.89\ J$

In this system as the potential and kinetic energy is conserved from work energy equivalence we get

$W=P-K\\\Rightarrow W=2.89-3.3354\\\Rightarrow W=-0.4454\ J$

The work done by friction is -0.4454 Joules

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3 years ago

A student walks to the right 25-m along the 800 hall in 15-s. They turn around and walk 15-m to the left in 8.0-s. Calculate the

Ludmilka [50]

Answer:

Explanation:

Total distance covered = 25 + 15 = 40 m

Total time = 15 + 8 = 23 s

Average speed = total distance covered / total time

= 40 / 23

= 1.74 m / s

Total displacement = 25 - 15 = 10 m

Total time = 15 + 8 = 23 s

Average velocity = total displacement / total time

= 10 / 23

= .434 m / s to the right .

3 0

3 years ago

(LC)Light fixtures and placement that create shadows on the set, that obscure or completely hide action in certain areas of the

Sedaia [141]

The correct answer is true.

It is true that light fixtures and placement that create shadows on the set, that obscure or completely hide action in certain areas of the set, or that change as the main character’s emotional state changes are all ways that lighting can be used to heighten the drama and suspense in dramatic films.

Lighting plays an important role in film making because it can create scenes that enhance the de drama of the moment or the right mood that the director wants to share. Lighting in the film is an art because the basic principle is that the scene needs to look natural. From that principle, filmmakers and light specialist cand create many kinds of dramatic or jubilation moments if they know how to apply light principles to each scene.

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3 years ago

A 30 kg student drops down from the monkey bars. The acceleration due to gravity is -9.8 m/s^2. Neglecting air drag, what is the

Sholpan [36]

The net force on the student is A) -294 N

Explanation:

Neglecting air resistance, there is only one force acting on the student: the force of gravity, which is given by

$F=mg$