Answer:
a=∆v/∆t
Explanation:
The definition of Acceleration is the change in velocity in a given time. So this means you first calculate ∆v (Change in velocity), and you calculate ∆t which is the time taken to apply that change in velocity. Then you find a= ∆v/∆t. This gives us the equation of Acceleration.
Answer:
ratio of tangential velocity of satellite b and a will be 0.707
Explanation:
We have given distance of satellite B from satellite A is twice
So 
Tangential speed of the satellite is given by
, G is gravitational constant. M is mass of satellite and r is distance from the earth
We have to find the ratio of tangential velocities of b and a
From the relation we can see that tangential velocity is inversely proportional to square root of distance from earth
So 
So ratio of tangential velocity of satellite b and a will be 0.707
Explanation:
When there is a constant unbalanced force applied in the same direction as the motion, speed will increase and acceleration will remain constant. When there is an increasing unbalanced force applied in the same direction as the motion, speed will increase and acceleration will increase.
According to newton's 2nd law
F = ma
F ∝ a
meaning when F increases , a increases and vice versa
Answer:
D. 214 kPa
Explanation:
The absolute pressure is given by:
where
p is the absolute pressure
is the atmospheric pressure
is the gauge pressure
In this problem, we have
So, the atmospheric pressure is
Respuesta:
24m
Explicación:
Según la ecuación de movimiento
v = u + en
Dado
Velocidad final v = 12 m / s
velocidad inicial u = 0 m / s
tiempo t = 4s
Sustituir
12 = 0 + 4a
a = 12/4
a = 3 m / s²
Lo siguiente es obtener la distancia;
S = ut + 1 / 2at²
S = 0 (4) + 1/2 (3) (4) ²
S = 3 * 16/2
S = 48/2
S = 24 m
Por lo tanto, la distancia requerida es de 24 m.
