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miss Akunina [59]
3 years ago
9

A large truck collides head-on with a small compact car. During the collision: (A) the truck exerts a greater amount of force on

the car than the car exerts on the truck. (B) the car exerts a greater amount of force on the truck than the truck exerts on the car. (C) neither exerts a force on the other, the car gets smashed simply because it gets in the way of the truck. (D) the truck exerts a force on the car but the car does not exert a force on the truck. (E) the truck exerts the same amount of force on the car as the car exerts on the truck.
Physics
1 answer:
Yakvenalex [24]3 years ago
7 0

Answer:

A The truck exerts greater force

Explanation:

During collision the truck exerts greater force due to its much larger mass coupled with the speed than the car exerts on it thereby damaging the car more

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Answer:

1- The acceleration of the object is larger in magnitude the smaller the radius of the circle.

Explanation:

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a = \frac{v^2}{r}

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Answer:

a. -12.7 Nm

b. -7.9 rad/s^2

Explanation:

I have attached an illustration of a solid disk with the respective forces applied, as stated in this question.

Forces applied to the solid disk include:

F_1 = 90.0N\\F_2 = 125N

Other parameters given include:

Mass of solid disk, M = 24.3kg

and radius of solid disk, r = 0.364m

a.) The formula for determining torque (T), is T = r * F

Hence the net torque produced by the two forces is given as a summation of both forces:

T = T_{125} + T_{90}\\= -r(125)sin90 + r(90)sin90\\= 0.364(-125 + 90)\\= -12.7 Nm

b.)  The angular acceleration of the disk can be found thus:

using the formula for the Moment of Inertia of a solid disk;

I_{disk} = {\frac{1}{2}}Mr^2

where M = Mass of solid disk

and r = radius of solid disk

We then relate the torque and angular acceleration (\alpha) with the formula:

T = I\alpha \\-12.7 = ({\frac{1}{2}}Mr^2)\alpha \\\alpha  = -{\frac{12.7}{1.61}} = -7.9 rad/s^2

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Explanation:

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