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Georgia [21]
3 years ago
9

For an object like a planet, with a typical temperature of a few hundred kelvin, what kind of blackbody radiation would it princ

ipally emit
Physics
1 answer:
navik [9.2K]3 years ago
6 0

Answer:

Low-temperature blackbody

Explanation:

There are 3 types of blackbody temperatures.

Low-temperature blackbody

High temperature extended area blackbody

High-temperature cavity blackbody

A Low-temperature blackbody is a type of black body radiation that has the range of -40° C to 175° C, typically between 233 K and 448 K. A perfect fit for the temperature range mentioned in the question, "a few hundred Kelvin". Therefore, it's the kind of blackbody temperature that the object would emit.

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You dip your finger into a pan of water twice each second,producing waves with crests that are separated by 0.17 m.
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Answer:

a) 2Hz

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Explanation:

a) Frequency is defined as the number of oscillations completed by a wave in one second.

If my finger is dipped into a pan of water twice each second, it means that my hand has made 2 oscillations through the water in one second. An oscillation is a to and fro movement of a particle, body or wave through a medium.

Based on the conclusion, the frequency of the waterwaves will be 2Hertz or 2cycles/sec.

2) Period T of a wave is defined as the time taken by a wave to complete one oscillation. It is the reciprocal of the frequency of a wave.

T = 1/F

Given frequency = 2Hertz

T = 1/2

T = 0.5seconds

Period of the water wave is 0.5seconds

c) speed of the wave v is expressed according to the relationship:

velocity = frequency × wavelength

Given:

Frequency = 2Hertz

Wavelength = 0.17m (Since it is the difference between two successive crest or trough of a wave)

Velocity = 2×0.17

Velocity = 0.34m/s

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