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3 years ago

Explain how a generator creates electricity.

Physics

2 answers:

Solnce55 [7]3 years ago

6 0

Answer:

Explanation:

Interesting question. Basically, it depends on the type of generator. Basically a generator converts mechanical energy into electrical energy.

How does it work? Well let's see an example:

When you have two magnets, they attract to each other right? Well, the reason of this atraction is called "Magnetic Field". When you put a magnet close to another there will be a magnetic force, in other words, one force that will cause any metalic object to be attracted to the magnect. So we could say that there's a magnetic field around the magnet that will make metalic objects be attracted to this magnet.

So, according to physics, if a magnetic field is changing over time it could induce voltage in a conductor.

How can a magnetic field change over time? Well, you can take two magnets and move them with your hands and the magnetic field will be changing over time.

So far we know that, if we change the magnetic field over time, we will generate electricity. But, how do we make the magnetic field change?

Well basically it depends on the type of generator. There are hydroelectric power plants, wind power plants, thermal power plants, etc. Basically, the difference between those power plants is how we make the magnetic field change.

In the case of wind power plants, the wind moves the turbines, that moves the axis of the generator that will make the magnetic field change over time.

In real life, two magnets will never induce enough voltage to power an entire house or a city. So instead of magnets we use what is called "electromagnet", which is basically like creating a magnet with electricity.

This is because when current is flowing through a conductor, it behaves exactly LIKE A MAGNET. So, if instead of magnets we just make current flow through conductors, then the effect will be the same. The magnetic field will change over time when the axis is moved.

I hope I answered your question.

faust18 [17]3 years ago

6 0

Answer:

An armature spins inside the magnetic field created by a permanent magnet. The magnetic field induces a current in the armature, generating electricity.

Explanation:

sample answer on edge

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R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the d

padilas [110]

The provided question's answer is "Schwarzschild radius".

The conversion factor between mass and energy is the speed of light squared.

GM/r stands for gravitational potential energy, also known as energy per unit mass.

GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."

The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).

Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.

The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.

So, the given equation is of Schwarzschild radius.

Learn more about Schwarzschild radius here:

brainly.com/question/12647190

#SPJ10

3 0

2 years ago

At noon, ship A is 140 km west of ship B. Ship A is sailing east at 30 km/h and ship B is sailing north at 25 km/h. How fast (in

Luba_88 [7]

Answer:

The rate of change of distance between the two ships is 18.63 km/h

Explanation:

Given;

distance between the two ships, d = 140 km

speed of ship A = 30 km/h

speed of ship B = 25 km/h

between noon (12 pm) to 4 pm = 4 hours

The displacement of ship A at 4pm = 140 km - (30 km/h x 4h) =

140 km - 120 km = 20 km

(the subtraction is because A is moving away from the initial position and the distance between the two ships is decreasing)

The displacement of ship B at 4pm = 25 km/h x 4h = 100 km

Using Pythagoras theorem, the resultant displacement of the two ships at 4pm is calculated as;

r² = a² + b²

r² = 20² + 100²

r = √10,400

r = 101.98 km

The rate of change of this distance is calculated as;

r² = a² + b²

r = 101.98 km, a = 20 km, b = 100 km

$2r(\frac{dr}{dt} ) = 2a(\frac{da}{dt} ) + 2b(\frac{db}{dt} )\\\\r(\frac{dr}{dt} ) = a(\frac{da}{dt} ) + b(\frac{db}{dt} )\\\\101.98(\frac{dr}{dt} ) = 20(-30 ) + 100(25 )\\\\101.98(\frac{dr}{dt} ) = -600 + 2,500\\\\101.98(\frac{dr}{dt} ) = 1900\\\\\frac{dr}{dt} = \frac{1900}{101.98} = 18.63 \ km/h$

5 0

3 years ago

What fraction of the space within the atom is occupied by the nucleus?

ValentinkaMS [17]

Answer:

Approximately 6.8 x 10⁻¹⁵

Explanation:

To be able to get this fraction, there are some things we need to know.

1. The radius of nucleus = 1.0 x 10⁻¹³ cm

2. The radius of hydrogen atom = 52.9 pm

3. Volume of sphere = V1/V2 = (R1/R2)^3

4. 1 picometer (pm) = 10^-10 cm

CHECK ATTACHMENT FOR Step by step solution to the answer

3 0

3 years ago

What type of force cause an object to accelerate??

Olin [163]

ANY force causes an object to accelerate, just as long as there are not
some other forces on the object that cancel out the first one.

Are you looking for the answer ... an "UNBALANCED" force ?
That's a very poor way to describe it, because there's no such thing
as a balanced or unbalanced force. The thing that's balanced or
unbalanced is a GROUP of forces, not a single force.

8 0

3 years ago

A ball is thrown straight up from the edge of the roof of a building. A second ball is dropped from the roof a time of 1.19 s s

ziro4ka [17]

A) Initial velocity of ball 1: 9.53 m/s upward

B) Height of the building: 6.48 m

C) Maximum velocity: 11.7 m/s

D) Minimum velocity: 5.83 m/s

Explanation:

The y-position of the 1st ball at time t is given by the equation for free fall motion:

$y_1 = h + v_0 t - \frac{1}{2}gt^2$ (1)

where

h = 21.0 m is the initial height of the ball, the height of the building

$v_0$ is the initial velocity of the ball, upward

$g=9.8 m/s^2$ is the acceleration of gravity

The y-position of the 2nd ball instead, dropped from the roof 1.19 s later, is given by

$y_2 = h-\frac{1}{2}g(t-1.19)^2$

where

h = 21.0 m is the initial height of the ball, the height of the building

t' = 1.19 s is the delay in time of the 2nd ball (we can verify that at t = 1.19 s, then $y_2=h$ , so the ball is still on the roof

The 2nd ball reaches the ground when $y_2=0$ , so:

$0=h-\frac{1}{2}g(t-1.19)^2\\0=(21.0)-4.9(t^2-2.38t+1.42)\\4.9t^2-11.66t-14.04=0$

Which has two solutions:

t = -0.88 s (negative, we discard it)

t = 3.26 s (this is our solution)

The 1st ball reaches the ground at the same time, so we can substitute t = 3.26 s into eq.(1) and $y_1=0$ , so we find the initial velocity:

$0=h+v_0 t -\frac{1}{2}gt^2\\v_0 = \frac{1}{2}gt-\frac{h}{t}=\frac{1}{2}(9.8)(3.26)-\frac{21.0}{3.26}=9.53 m/s$

In this case, the height of the building h is unknown, while the initial velocity of ball 1 is known:

$v_0 = 8.70 m/s$

When the two balls reach the ground at the same time, there position is the same, so we can write:

$y_1=y_2\\h+v_0 t - \frac{1}{2}gt^2 = h-\frac{1}{2}g(t-1.19)^2$

Solving the equation, we find:

$v_0t=1.19gt-\frac{1}{2}g(1.19)^2\\t=\frac{0.5g(1.19)^2}{1.19g-v_0}=2.34 s$

This is the time at which both balls reache the ground; and substituting into the eq. of ball 2, we find the height of the building:

$0=h-\frac{1}{2}g(t-1.19)^2\\h=0.5g(t-1.19)^2=0.5(9.8)(2.34-1.19)^2=6.48 m$

If $v_0$ is greater than some value $v_{max}$ , then there is no value of h such that the two balls hit the ground at the same time. This situation occurs when the demoninator of the formula found in part b:

$t=\frac{0.5g(1.19)^2}{1.19g-v_0}$

becomes negative: in that case, the time becomes negative, so no solution is possible.

The denominator becomes negative when

$1.19g-v_0 < 0$

Therefore when

$v_0>1.19g=(1.19)(9.8)=11.7 m/s$

So, if the initial velocity of ball 1 is greater than 11.7 m/s, the two balls cannot reach the ground at the same time.

There is also another condition that must be true in order for the two balls to reach the ground at the same time: the time at which ball 1 reaches the ground must be larger than 1.19 s (because ball 2 starts its motion after 1.19 s). This means that the following condition must be true

$t=\frac{0.5g(1.19)^2}{1.19g-v_0}>1.19$