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inna [77]
3 years ago
10

Faster-moving water can carry a greater load. true or false

Chemistry
2 answers:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

That is false

Explanation:

Just because it moves faster doesn't mean that it can carry and bigger load.

Talja [164]3 years ago
7 0

Answer:

False

Explanation:

can i get brainliest plz

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The pressure decreases as the temperature decreases, if volume and amount of gas do not change.
qaws [65]

Answer:

oh cool fact

Explanation:

8 0
3 years ago
During the process of evaporation, molecules of liquid water in oceans,
Rina8888 [55]

Answer:

Explanation:

solar energy

Heat from the sun, or solar energy, powers the evaporation process. It soaks up moisture from soil in a garden, as well as the biggest oceans and lakes. The water level will decrease as it is exposed to the heat of the sun.

8 0
3 years ago
A 10.0 g sample of propane, C3H8, was combusted in a constant-volume bomb calorimeter. The total heat capacity of the bomb calor
Liono4ka [1.6K]

Answer:

83ºC

Explanation:

A bomb calorimeter is an instrument used to measure the heat that release or absorb a particular reaction.

The reaction of combustion of propane is:

C₃H₈ +  5O₂ → 3 CO₂ + 4 H₂O ΔH = -2222kJ/mol

<em>1 mole of propane release 2222kJ</em>

10.0g of propane (Molar mass: 44.1g/mol).

10.0g ₓ (1mol/ 44.1g) = <em>0.227 moles of C₃H₈</em>

If 1 mole of propane release 2222kJ, 0.227moles will release (Release because molar heat is < 0):

0.227 moles of C₃H₈ ₓ (2222kJ / mol) = 504kJ.

Our calorimeter has a constant of 8.0kJ/ºC, that means if there are released 8.0kJ, the bomb calorimeter will increase its temperature in 1ºC. As there are released 504kJ:

504kJ ₓ (1ºC / 8.0kJ) = 63ºC will increase the temperature in the bomb calorimeter.

As initial temperature was 20ºC, final temperature will be:

<h2>83ºC</h2>
8 0
4 years ago
Predict the boiling point of water at a pressure of 1.5 atm.
Lina20 [59]

Answer:

100.8 °C

Explanation:

The Clausius-clapeyron equation is:

ln\frac{P_{1} }{P_{2}} =-Δ\frac{H_{vap}}{r} (\frac{1}{T_{2}}-\frac{1}{T_{1}}  )

Where 'ΔHvap' is the enthalpy of vaporization; 'R' is the molar gas constant (8.314 j/mol); 'T1' is the temperature at the pressure 'P1' and 'T2' is the temperature at the pressure 'P2'

Isolating for T2 gives:

T_{2}=(\frac{1}{T_{1}} -\frac{Rln\frac{P_{2}}{P_{1}} }{Delta H_{vap}}

(sorry for 'deltaHvap' I can not input symbols into equations)

thus T2=100.8 °C

7 0
3 years ago
Ethanol is a/an A. organic acid. B. substituted hydrocarbon. C. aromatic hydrocarbon. D. carbohydrate.
Rudik [331]
Ethanol is a substituted hydrocarbon. The "ol" suffix used in ethanol is for the functional group -OH, or alochol group. When any functional group is attached to a pure hydrocarbon, that hydrocarbon shows properties of that functional group. 
For ethane as well, which have molecular formula of C2H6, when one hydrogen is substituted by one -OH group it becomes C2H5OH which we call as ethanol or ethyl alcohol. If two hydrogen are substituted, it becomes -diol and as such.
There are number of ways to prepare ethanol by pure hydrocarbon. Generally ethanol can be prepared by fermentation of starch and molasses. Also various organic reaction gives ethanol as product. When ethene is  reacted with steam catalysed by phosphoric acid.
8 0
3 years ago
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