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Zigmanuir [339]
3 years ago
8

The _______ are found on the left side of the arrow in a chemical reaction.

Chemistry
1 answer:
Snezhnost [94]3 years ago
4 0
The reactants are found on the left side, the products are found on the right side.
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Write the nuclear equation to describe the alpha decay of 243 95 Am
motikmotik

Answer:

Here's what I get.

Explanation:

Your unbalanced nuclear equation is:

_{95}^{243}\text{Am} \longrightarrow \, _{x}^{y}\text{Z} +\, _{2}^{4}\text{He}

The main point to remember in balancing nuclear equations is that the sums of the superscripts and the subscripts must be the same on each side of the equation.  

Then

  95 = x + 2, so x =   95 - 2 =    93

243 = y + 4, so y = 243 - 4 = 239

Element 93 is neptunium, so the nuclear equation becomes

_{95}^{243}\text{Am} \longrightarrow \, _{93}^{239}\text{Np} + \, _{2}^{4}\text{He}  

7 0
3 years ago
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When interviewed, Mr. Harrison was discussing barometric pressure and the low-pressure system moving in that may cause a change
Zarrin [17]

A meteorologist?? I could be totally wrong though! :)


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3 years ago
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Why are alphabets in the order they are?
sineoko [7]
Its arbitrary. It was developed on the greek phoenetic system and never reallybwas explained.
4 0
3 years ago
HELP! 10 pts!! || Which does NOT describe a water molecule?
AVprozaik [17]

Answer:

C.)

Explanation:

Hope this helps:)

5 0
3 years ago
Calculate the pH of a buffer solution prepared by mixing 60.0 mL of 1.00 M lactic acid and 25.0 mL of 1.00 M sodium lactate.
marshall27 [118]
This problem could be solved easily using the Henderson-Hasselbach equation used for preparing buffer solutions. The equation is written below:

pH = pKa + log[(salt/acid]

Where salt represents the molarity of salt (sodium lactate), while acid is the molarity of acid (lactic acid). 

Moles of salt = 1 mol/L * 25 mL * 1 L/1000 mL = 0.025 moles salt
Moles of acid = 1 mol/L* 60 mL * 1 L/1000 mL = 0.06 moles acid
Total Volume = (25 mL + 60 mL)*(1 L/1000 mL) = 0.085 L

Molarity of salt = 0.025 mol/0.085 L = 0.29412 M
Molarity of acid = 0.06 mol/0.085 L = 0.70588 M

Thus,
pH = 3.86 + log(0.29412/0.70588)
pH = 3.48
4 0
3 years ago
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