Answer: 1-Phenyl ethyl radical is formed as an intermediate in the reaction and since Phenyl ethyl radical has a trigonal planar geometry so it is a planar molecule having two faces. So Br radical radical can recombine with the two faces with equal probability leading to a racemic mixture in 50:50ratio of products.Hence two products are formed which are known as enatiomers.
Explanation:
When we irradiate the ethylbenzene with UV light , it leads to homolytic cleavage and 1- Phenyl ethyl free radical is generated.
Phenyl ethyl free radical is generated because it is very stable as it is on a secondary carbon center as well as on a benzylic position so it can be stabilized by the resonance as well as inductive effect at the secondary carbon center.
NBS(N-bromosuccinimide) is a source of bromine radical and provides bromine free radical.
Once the 1- Phenyl ethyl free radical is generated then bromine free radical can recombine with benzyl free radical leading to product formation.
Since 1- Phenyl ethyl free radical has a trigonal planar geometry so it is a planar molecule which has two faces and hence the radical recombination with bromine free radical can occur with either of the two faces available.
Kindly refer the attachments for structure as well as the mechanism of the reaction.
So two isomers which are enantiomers are produced are obtained.
Every time you see molecules, atoms, & particles think of avagadros #. (6.022 x 10^23)
Answer: 13.6 grams of H2O
Solution: (4.56x10^23) x (1 mol H2O/6.022x10^23) x (18 grams H2O/1 mol H2O) = 13.6 grams of H2O
Using dimensional analysis above makes these types of problems easy.
Answer: 20L of H2O
Explanation:
C3H8 + 5O2 → 3CO2 + 4H2O
Recall 1mole of a gas contains 22.4L at stp
5moles of O2 contains = 5 x 22.4 = 112L
4moles of H2O contains = 4 x 22.4 = 89.6L
From the equation,
112L of O2 produced 89.6L H2O
There for 25L of O2 will produce XL of H2O i.e
XL of H2O = (25 x 89.6)/112 = 20L
2Al + 6HCl -> 2AlCl3 + 3H2
Answer:
<em>Acylation can be used to prevent rearrangement reactions that would normally occur in alkylation. </em>