17. SiH3P How do you create a Lewis structure for this formula?
1 answer:
Answer:
See attached picture.
Explanation:
Hello,
In this case, considering that Lewis structures are drawn in order to show up the bonding among equal or different atoms via their valence electrons, since hydrogen has one valence electron, silicon four and phosphorous five, the most suitable way to draw and attain the octet for both silicon and phosphorous is by bonding them via a double bond, one hydrogen bonded to the phosphorous and two hydrogen atoms bonded to the silicon as shown on the attached picture, wherein you can count eight electrons for both phosphorous and silicon.
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The Lewis Structure of HCN is shown below,
Number of Bonding Electrons:
In HCN Hydrogen is bonded to Carbon through single bond and Nitrogen is bonded to Carbon through Triple Bond. Single bond is formed by two bonding electrons, while, triple bond is formed by six bonding electrons, Hence,
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons:
In HCN there is only one lone pair of electron present on Nitrogen atom which is not taking part in bonding. Hence,
Number of Non-Bonding Electrons = 2
Result:
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons = 2
Number of Bonding Electrons:
In HCN Hydrogen is bonded to Carbon through single bond and Nitrogen is bonded to Carbon through Triple Bond. Single bond is formed by two bonding electrons, while, triple bond is formed by six bonding electrons, Hence,
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons:
In HCN there is only one lone pair of electron present on Nitrogen atom which is not taking part in bonding. Hence,
Number of Non-Bonding Electrons = 2
Result:
Number of Bonding Electrons = 8
Number of Non-Bonding Electrons = 2