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frutty [35]
3 years ago
10

The weight of an astronaut plus his space suit on the moon is only 291 n. how much (in n) do they weigh on earth? (the accelerat

ion due to gravity on the moon is 1.67 m/s2.)
Physics
1 answer:
Oksanka [162]3 years ago
6 0
Weight on the Moon = 291 N.
W = g · m, where m stays for the mass and on the Moon g = 1.67 m/s²
291 N = 1.67 m/s² · m
m = 291 kg m / s² : 1.67 m/s²
m = 174.25 kg
Weight on Earth = 9.81 m/s² · 174.25 kg = 1,709.4 N
Answer:
The weight of an astronaut on Earth is 1,709.4 N.



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If the car is traveling at a velocity of 15 m/s, what is the approximate centripetal acceleration of the car?.
BaLLatris [955]

The vehicle's centripetal acceleration is equal to 22.5m/s²

Radius, r = 10 meter

Speed, V = 15 m/s

To ascertain the car's centripetal acceleration

A(c) = V²/R

We obtain the following when we enter the formula's parameters:

A(c) = 152/10

A(c) = 225/10

A(c) = 22.5m/s²

<h3>What is Centripetal acceleration ?</h3>

When an item moves in a circular route, one of its motion characteristics is centripetal acceleration. Any motion in a circle with an acceleration vector pointing in the direction of the circle's centre is referred to as centripetal acceleration.

  • Centripetal forces cause accelerations at the centripetal axis. With the exception of the Earth's rotation around the Sun, any satellite's circular motion around a celestial body is brought on by the centripetal force produced by their mutual gravitational pull.

Hence, Centripetal acceleration is

22.5 m/s²

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7 0
1 year ago
PLS HELP!!
stealth61 [152]

Answer:

B

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8 0
3 years ago
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A measurement has high<br> when it is very close to the<br> true value?
jarptica [38.1K]

Answer:

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Accuracy means making measurements that are close to the value precision means making measurement that are close in value to eachother but not necessarily close to the true value.

I hope this helps! If not sorry.

7 0
3 years ago
6. A pitcher throws a ball toward home plate 18.39 meters away. If the ball is traveling at a constant 40.0 m/s, how long does i
Kruka [31]
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3 0
3 years ago
A car travels at a steady 40.0 m/s around a horizontal curve of radius 200 m. What is the minimumcoefficient of static friction
zhenek [66]

Answer:

c. 0.816

Explanation:

Let the mass of car be 'm' and coefficient of static friction be 'μ'.

Given:

Speed of the car (v) = 40.0 m/s

Radius of the curve (R) = 200 m

As the car is making a circular turn, the force acting on it is centripetal force which is given as:

Centripetal force is, F_c=\frac{mv^2}{R}

The frictional force is given as:

Friction = Normal force × Coefficient of static friction

f=\mu N

As there is no vertical motion, therefore, N=mg. So,

f=\mu mg

Now, the centripetal force is provided by the frictional force. Therefore,

Frictional force = Centripetal force

f=F_c\\\\\mu mg=\frac{mv^2}{R}\\\\\mu=\frac{v^2}{Rg}

Plug in the given values and solve for 'μ'. This gives,

\mu = \frac{(40\ m/s)^2}{200\ m\times 9.8\ m/s^2}\\\\\mu=\frac{1600\ m^2/s^2}{1960\ m^2/s^2}\\\\\mu=0.816

Therefore, option (c) is correct.

7 0
3 years ago
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