Answer:
given,
initial velocity = 11.5 m/s
acceleration = 0.5 m/s²
time = 7 s
a) using equation of motion
v = u + a t
v = 11.5 + 0.5 × 7
v = 15 m/s
b) 
s = 92.75 m
distance traveled by racer with final velocity
d = 300 - 92.75
= 207.25 m
time spend to travel 207.25
t = 13.82 s
total time spent to travel 300m
t = 7 + 13.82
t = 20.82 s
time required to travel 300 m with initial velocity
= 26.09 s
time saved due to acceleration
t = 26.09 - 20.82 = 5.27 s
c) second racer is 5 m apart from the first one
distance traveled by the second racer till first one finishes the race
distance behind the leader
d = 300 -5 -245.676 = 49.34 m
time behind the winner
Answer:
a) a = 2.383 m / s², b) T₂ = 120,617 N
, c) T₃ = 72,957 N
Explanation:
This is an exercise of Newton's second law let's fix a horizontal frame of reference
in this case the mass of the sleds is 30, 20 10 kg from the last to the first, in the first the horizontal force is applied.
a) request the acceleration of the system
we can take the sledges together and write Newton's second law
T = (m₁ + m₂ + m₃) a
a = T / (m₁ + m₂ + m₃)
a = 143 / (10 +20 +30)
a = 2.383 m / s²
b) the tension of the cables we think through cable A between the sledges of 1 and 20 kg
on the sled of m₁ = 10 kg
T - T₂ = m₁ a
in this case T₂ is the cable tension
T₂ = T - m₁ a
T₂ = 143 - 10 2,383
T₂ = 120,617 N
c) The cable tension between the masses of 20 and 30 kg
T₂ - T₃ = m₂ a
T₃ = T₂ -m₂ a
T₃ = 120,617 - 20 2,383
T₃ = 72,957 N
<em>Answer:</em>
<em>The answers are: </em>
- <em>A-which is the image is always right side up.</em>
- <em>E-the image is virtual</em>
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<em>Explanation: MY EXPLANATION IS YOU ARE WELCOME BIG DOG 100..</em>
<em></em>
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Answer: D. the wave has traveled 97.2 cm in 1 second.
Explanation:
Got it right on edge, hope this helps :)
