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3 years ago

The total magnification of a specimen being viewed with a 10X ocular lens and a 40X objective lens is _____.

Physics

1 answer:

raketka [301]3 years ago

3 0

Answer:

total magnification = 400 X

Explanation:

given data

ocular lens = 10 X

objective lens = 40 X

to find out

total magnification

solution

we know that total magnification is express as

total magnification = Objective magnification × ocular magnification .................1

put here value we get

total magnification = 10 × 40

total magnification = 400 X

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3 years ago

During 57 seconds of use, 330 C of charge flow through a microwave oven. Compute the size of the electric current.

swat32

Answer:

5.78amps

Explanation:

Given data

Time t= 57 seconds

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3 years ago

Suppose a moving car has 2000 J of kinetic energy. If the carʹs speed doubles, how much kinetic energy would it then have?

Bond [772]

Answer:

option A

Explanation:

given,

Kinetic energy of the car = 2000 J

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$KE_1 = \dfrac{1}{2}mv^2$

$2000= \dfrac{1}{2}mv^2$ ........(1)

now, speed of the car is doubled

v' = 2 v

$KE_2 = \dfrac{1}{2}mv'^2$

$KE_2 = \dfrac{1}{2}m(2v)^2$

from equation (1)

$KE_2 = 4\times \dfrac{1}{2}m(v)^2$

$KE_2 = 4\times 2000$

$KE_2 = 8000\ J$

Hence, the Kinetic energy would be equal to 8000 J.

The correct answer is option A.

8 0

3 years ago

A tank holds a 1.44-m thick layer of oil that floats on a 0.98-m thick layer of brine. Both liquids are clear and do not intermi

denpristay [2]

Answer:

Angle of ray makes with the vertical is 62.1 degree

Explanation:

As per the ray diagram we know that the angle of incidence on oil brine interface will be given as

$tan\theta_i = \frac{0.7}{0.98}$

$\theta_i = 35.5^0$

now by Snell'a law at that interface we have

$\mu_1 sin\theta_i = \mu_2 sin \theta_r$

now we will have

$1.52 sin35.5 = 1.40 sin\theta_r$

$\theta_r = 39.12^0$

now this is the angle of incidence for oil air interface

so now again by Snell's law we will have

$\mu_2 sin\theta_i' = \mu_{air} sin\theta$

$1.40 sin39.12 = 1 sin\theta$

$\theta = 62.1^0$

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3 years ago