Answer:
B. decreases while his angular speed remains unchanged.
Explanation:
His angular speed will always be the same as the wheel's angular speed, which remains constant as it's in uniform motion. As for linear speed, which is defined as the product of angular speed and distance r to the center of rotation, and his distance to center is decreasing, his linear speed must be decreasing as well.
I am using the equation F=ma (force equals mass times acceleration) to solve these problems.
1. You are looking for force, and have mass and acceleration. You just plug in the values for mass and acceleration to get the force needed.
F=(15kg)(5m/s^2)
F=75N
2. Again, you are looking for force, and just need to plug in the values for mass and acceleration
F=(3kg)(2.4m/s^2)
F=7.2N
3. In this problem, you have force and mass, but need to find acceleration. To do this, you need to get acceleration alone on one side of the equation - divide each side by m. Your equation will now be F/m=a
a=(5N)/(3.7kg)
a=18.5m/s^2
I did not use significant figures. Let me know if you need to do that and need any help on that. Hope this helps!
Answer:
Maximum height attained by the model rocket is 2172.87 m
Explanation:
Given,
- Initial speed of the model rocket = u = 0
- acceleration of the model rocket =
- time during the acceleration = t = 2.30 s
We have to consider the whole motion into two parts
In first part the rocket is moving with an acceleration of a = 85.0 
for the time t = 2.30 s before the fuel abruptly runs out.
Let 
be the height attained by the rocket during this time intervel,
And Final velocity at that point be v
Now, in second part, after reaching the altitude of 224.825 m the fuel abruptly runs out. Therefore rocket is moving upward under the effect of gravitational acceleration,
Let '
' be the altitude attained by the rocket to reach at the maximum point after the rocket's fuel runs out,
At that insitant,
- initial velocity of the rocket = v = 195.5 m/s.
- a =
- Final velocity of the rocket at the maximum altitude =
From the kinematics,
Hence the maximum altitude attained by the rocket from the ground is
Try practicing basketball in your free time and learn to love it. You can also apply to schools or teams that teaches basketball more. Get good teachers.
Answer:
The linear speed of scratch is 45.55 cm/dec
Explanation:
The scratch located from the center at radial distance = 14.5 cm.
Each minute the skip of scratch when disco record played = 30 times
Since, the scratch on the disc start revolving when disc is played and in one minute the scratch revolve 30 times. Therefore, the revolution = 30 RPM
Below is the calculation of linear speed of the scratch.
