When trying to describe how an object falls, Newton found that the speed of the object increased in every split second and no mathematics currently used to describe the object at any moment in time.
We want to find how much momentum the dumbbell has at the moment it strikes the floor. Let's use this kinematics equation:
Vf² = Vi² + 2ad
Vf is the final velocity of the dumbbell, Vi is its initial velocity, a is its acceleration, and d is the height of its fall.
Given values:
Vi = 0m/s (dumbbell starts falling from rest)
a = 10m/s² (we'll treat downward motion as positive, this doesn't affect the result as long as we keep this in mind)
d = 80×10⁻²m
Plug in the values and solve for Vf:
Vf² = 2(10)(80×10⁻²)
Vf = ±4m/s
Reject the negative root.
Vf = 4m/s
The momentum of the dumbbell is given by:
p = mv
p is its momentum, m is its mass, and v is its velocity.
Given values:
m = 10kg
v = 4m/s (from previous calculation)
Plug in the values and solve for p:
p = 10(4)
p = 40kg×m/s
Answer:
you were sopposed to divide
Explanation:
I believe it’s B. Electrons
Answer:
The mass of the solid cylinder is 
Explanation:
From the question we are told that
The radius of the grinding wheel is 
The tangential force is 
The angular acceleration is 
The torque experienced by the wheel is mathematically represented as
Where I is the moment of inertia
The torque experienced by the wheel can also be mathematically represented as
substituting values
So
So
This moment of inertia can be mathematically evaluated as
substituting values
=>
