Answer:
Explanation:
Gold (111) Chloride:
AuCl₃
The oxidation state of gold is +3.
Chlorine is present in group seventeen and have seven valance electrons . Thus it accept one electron to complete the octet and show oxidation state -1.
When it react with gold(III) three chlorine atoms are combine with one gold atom to make compound overall neutral.
Calcium Carbonate:
CaCO₃
Carbonate formula is CO₃²⁻ . It means it carry -2 charge . Calcium is present in group two. It has two valance electrons and lose them to get complete octet thus shows +2 oxidation state.
When it combine with carbonate the overall compound is neutral because -2 and +2 charges cancel each other.
Hydrobromic Acid
HBr
Hydrogen has one electron while bromine has seven valance electrons. Bromine require one more electron to complete the octet. It react with hydrogen by sharing of one electron of hydrogen and form polar covalent compound.
Answer:
Explanation:
Hello!
In this case, since the formula for the calculation of molarity is:
Whereas we can compute the moles of the solute as shown below, making sure the volume is in liters:
Thus, by plugging in we obtain:
Next, since the molar mass of NaCl is 58.44 g/mol, we obtain the following mass:
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There will be three electrons in the outer shell.
Answer:
Oxygen and Carbon are in the non-metal section. Both are in 2nd period while Carbon is in group 4A and Oxygen is in group 6A.
Oxygen has more valence electrons than carbon. I wish I could give you a more accurate explanation why on paper, but all you need to do is count the electrons on the largest shell.
Here's the orbital notation of Carbon: 1s^2 2s^2 2px^1 py^1
Carbon's largest shell is 2. Count the electrons on shell 2, and you get 4 valence electrons.
Orbital notation of Oxygen: 1s^2 2s^2 2px^2 py^1 pz^1
Oxygen's largest shell is 2. So, like with carbon, count the electrons on the largest shell. You get 6.
There is a way easier way of interpreting this where you do not even have to write the orbital notation. I wish I can explain, but just know the periods and the group numbers.
