For a molecule AB2, 3.5g of A represents one molar fraction, and 8.00g B represents 2 molar fractions (or 4.0+4.0). Therefore, a direct ratio can be given as 3.5:4.0, or 1:1.14. This means a molecule AnBm will give a mass ratio for A:B of n:1.14xm
For a molecule AB, for every 1g of A, you will have 1.14g of B.
For a molecule AB2, for every 1g of A, you will have 2.28g of B.
For a molecule A2B3, for every 1g of A, you will have (1.14x3/2) 1.71g of B.
Answer: 2.8 moles of copper (Il) sulfide 
will be produced from 2.8 moles of sulphur.
Explanation:
The balanced chemical reaction is:
According to stoichiometry :
1 mole of 
produce = 1 mole of copper (Il) sulfide
Thus 2.8 moles of will produce=
of copper (Il) sulfide
Thus 2.8 moles of copper (Il) sulfide will be produced from 2.8 moles of sulphur.
I might go with d it seems right to me hope this helps.
Answer:
Crystal field splitting is the difference in energy between d orbitals of ligands. Crystal field splitting number is denoted by the capital Greek letter Δ. Crystal field splitting explains the difference in color between two similar metal-ligand complexes.
Answer:
The empirical formula is SF6 (option E)
Explanation:
Step 1: Data given
Mass of sulfur = 3.21 grams
Mass of fluorine = 11.4 grams
Molar mass sulfur = 32.065 g/mol
Molar mass fluorine = 19.00 g/mol
Step 2: Calculate moles
Moles = mass /molar mass
Moles sulfur = 3.21 grams / 32.065 g/mol
Moles sulfur = 0.100 moles
Moles fluorine = 11.4 grams / 19.00 g/mol
Moles fluorine = 0.600 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
S: 0.100 / 0.100 = 1
F : 0.600 / 0.100 = 6
The empirical formula is SF6 (option E)
