Density does not change with the amount of matter.
The density of water is 1 g/mL whether you have 1 mL or 1000 mL of water. Density is an i<em>ntensive </em>property.
Mass, volume, and weight change with the quantity of matter. For example, the mass of 1000 mL of water is greater than the mass of 1 mL of water. Mass, volume, and weight are <em>extensiv</em>e properties.
Answer:
kJ
Explanation:
The thermochemical equation for decomposition of ammonium nitrate is:


Given mass= 50.0 kg =
(1kg=1000g)

According to stoichiometry:
1 mole of
gives = 82.1 kJ of heat
Thus
of
give =
kJ of heat
Thus
kJ of heat is evolved from the decomposition of 50.0 kg of ammonium nitrate.
Answer:
5.625 grams
Explanation:
Start your equation with what you have been given. Place the units you need in your answer on the right side of the equal sign.
225mg
----------- X ----------- X ------------- = ? g
lb
Now start to fill in your equation and use a conversions to get rid of the units you don't want. Convert mg into grams first. The child's weight (25 lb) is placed over 1 just to get the equation lined up properly so you can see how the units cancel out.
225 mg 1 g 25 lb 5.625 g
--------------- X --------------- X ------------- = ---------------
lb 1000 mg 1 1
The lb on the top and bottom cancel each other out and you are left with just grams. Even though it is over one, that is the same at just 5.625 grams.
Answer:
mixture
Explanation:
there was leftover components meaning there was something mixed into the liquid
Answer:
Yes, I would be able to hear the speaker clearly because the supposedly dropping off of sound as the distance gets farther is counteracted by "reverberations" inside the auditorium.
Explanation:
According to the "Inverse Square Law," if the distance from the sound source is doubled, the intensity of the sound will diminish by 6 decibels. This is true if the situation is in a <em>"free field,"</em> which means the sound has no reflection.
However, this is not the case in an "auditorium." An auditorium causes the <u>"reverberation" of sound. </u>This prolongs the resonance of the sound. So, this means that even if the sound drops off by a factor of 100 (20 decibels), due to reverberations, the height of the ceiling, the kind of wall and materials used in making the seats also affect the intensity of the sound waves. This is the reason why auditoriums are used as venues for <em>concerts, presentations and the like</em> where a <u>large group of people serve as the audienc</u>e.