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AysviL [449]
3 years ago
15

Three isotopes of oxygen are oxygen-16, oxygen-17 and oxygen-18. Write the symbol for each, including the atomic number and mass

number
Chemistry
1 answer:
sweet-ann [11.9K]3 years ago
6 0

oxygen-16 = 8 O 16

oxygen-17 = 8 O 17

oxygen-18 = 8 O 18

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Ideas of a band name
Oxana [17]

Answer:

Genre of music?

Explanation:

4 0
3 years ago
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In a previous problem, the empirical formula of a compound of phosphorus and oxygen was found to be p2o5. experimentation shows
agasfer [191]
The empirical formula for the compound is - P₂O₅
the empirical formula is the simplest ratio of whole numbers of components in a compound.
molecular formula is the actual ratio of components in a compound.
we have to first find the number of empirical units in the molecular formula 
molecular mass - 283.89 g/mol
mass of empirical formula - 283.8 g
number of empirical units - 283.89 g/mol / 283.8 g
number of empirical units - 1.000 
therefore empirical formula = molecular formula 
molecular formula - P₂O₅
3 0
3 years ago
What type of organic reaction produces both water and carbon dioxide
nalin [4]
I think it's called "<span>combustion." are there any answer choices though?

</span>
6 0
3 years ago
I need answersssss ... worth 20 POINTS!!
tester [92]

Not enough information!

Its pretty simple if you think about it.

7 0
3 years ago
How many grams of hydrogen chloride can be produced from 1g of hydrogen and 55g of chlorine? What is the limiting reactant?
vova2212 [387]

Answer:

The limiting reactant is hydrogen, and the grams HCl produced is 36.175 g.

Explanation:

Balanced equation is 2 H + Cl2 = 2 HCl.

First thing, convert grams to moles via using molar mass.

Molar mass for hydrogen is 1.0079 g/mol. 1g x 1 mol / 1.0079 g = 0.99216 mol.

Molar mass for chlorine is 70.906 g/mol. 55g x 1 mol / 70.906 g = 0.7756748 mol.

Next, determine which is the limiting reactant - probably the fastest way to do it is just to take one of the reactants, say it's the limiting one, and calculate how much of the other reactant would be needed if that really was the limiting reactant, and then compare it to the actual moles of reactant available.

If hydrogen was the limiting reactant at 0.992 mol, you'd need .496 mol of Cl2 to complete the reaction.

If chloride was the limiting reactant at 0.776 mol, you'd need 1.55 mol of H to complete the reaction.

Comparing these numbers to the amounts we actually have available, the limiting reactant is hydrogen.

Once you've determined that, just plug in the amounts to the balanced equation to get the number of moles of HCL produced, which in this case, is just 0.992 mol.

Now, reverse the process that you took to get the moles of reactant, and you have the grams of product produced.

0.992 mol x 36.4609 g / 1 mol = 36.175 g.

7 0
3 years ago
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