Answer: 714 g Al2O3
Explanation: Solution attached
First convert mass of O2 to moles
Do the mole ratio between O2 and Al2O3 from the balanced equation.
Convert moles of Al2O3 to mass using its molar mass.
This is a combustion reaction because it is being combined with oxygen. Then to balance you will put the number of carbons you have or 4 in front of the CO2 and then same with H2. Then you will add up the oxygen and divide it by two to get. 1, (13/2), 4, 5
Answer:
2/3 cup of semisweet chocolate
Answer: The initial partial pressures of
and
is 139.4 torr.
Explanation:
The equilibrium reaction is

initially conc. p p 0
At eqm. p-2x p-x 2x
Given: 

The expression for equilibrium constant is :

= 2x =115 torr
= (p-2x) = p-115 torr
= (p-x)= p-57.5 torr
Now put all the given values in this expression, we get


Therefore, the initial partial pressures of
and
is 139.4 torr.