The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7.
pH= -log[H+] - (i)
10^-3=H2So4
H+= 2×10-3
here ,
h2so4 ——— 2[H+] + so4^2-
thus [H+]= 2*10^(-3) because hydrogen ion has two moles
pH= -log[H+]
pH= -log(2×10^-3)
pH= 3-log2
pH= 3-log2pH= 2.7
The pH is 2.7
<h3>What is pH?</h3>
PH is the degree of alkalinity and acidicity in a solution.
Therefore, The hydronium and hydroxide concentrations of a solution that is 5.0 x 10-3 M H2SO4 is 2.7
Learn more about pH from the link below.
https://brainly.in/question/9937410
Deposition is the correct answer if I believe so
Complete dominance.... Hope this helps
To calculate the molarity you only need to know the number of moles in the solution and the volume of that solution. This exercise gives both and with that you divide moles by volume(usually in liters).
500 ml equals 0,5 L
molarity= number of moles/ volume
molarity=0,75 x 0,5
= 0,375 mol/L
