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krok68 [10]
3 years ago
8

The amount of space a material occupies is its

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
5 0

Answer:

—MASS is the amount of matter that makes up something. - VOLUME _ is the amount of space that a material takes up.

Explanation:

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What’s the difference between a learned behavior in an inherited behavior? Give one example of each
AleksAgata [21]

Answer:

A learned behavior is a behavior that develops during an animal's lifetime. Tying one's shoes or solving a math problem are examples of learned behaviors. An inherited behavior is a behavior that an animal is born with. It does not have to be taught. For example, a bird can build a nest for the first time without any help.

Explanation:

3 0
3 years ago
Read 2 more answers
Many classic experiments have given us indirect evidence of the nature of the atom. Which of the experiments below did not give
taurus [48]

The Rutherford experiment proved the Thomson “plum-pudding” model of the atom to be essentially correct did not give the results described and is denoted as option A.

<h3>What is Thomson “plum-pudding” model?</h3>

This model was proposed by J.J Thomson in which referred an atom as a sphere of positive charge, and negatively charged electrons are embedded in it to balance the total positive charge.

This model was incorrect and the Rutherford atomic model was adopted in which he described the electrons orbits about a tiny positive nucleus.

The nucleus contains protons and neutrons instead thereby making it the correct choice.

Read more about Atom here brainly.com/question/6258301

#SPJ1

The options include the following:

a.The Rutherford experiment proved the Thomson “plum-pudding” model of the atom to be essentially correct.

b.The Rutherford experiment was useful in determining the nuclear charge on the atom.

c.Milikan’s oil-drop experiment showed that the charge on any particle was a simple multiple of the charge on the electron.

d.The electric discharge tube proved that electrons have a negative charge

4 0
1 year ago
Read the excerpt from a reading passage titled "Matter and Energy: Evaporation and Condensation." Condensation An example of con
mestny [16]

Answer : The correct option is (C) : Dew forms on grass when water vapor forms when molecules cool and join together.

Explanation :

Air contains a small amount of water vapors. When the temperature of an object is lowered than the ambient temperature, the vapors get condensed and small water droplets are formed on the object.

During night time, when the temperature is lowered, the blades of grass become cool. As a result, the vapor molecules slow down and eventually come close to each other. They join together to form liquid water which gets deposited on the blades in the form of dew drops.

The only option that explains this process is option C.

3 0
3 years ago
What is the pH of an HCL solution if [H+]=0.03​
I am Lyosha [343]

Answer:

pH = 1.5

Explanation:

The pH is always equal to -log[H+].

Simply plug it into this formula to find the pH. In order to find the concentration from the pH, you can do:

10^{-pH} = [H+]

4 0
2 years ago
Read 2 more answers
In a similar experiment, a current of 2.15 amps ran for 8 minutes and 24 seconds. The temperature of the water was 26.0°C. The v
lord [1]

Answer:

\boxed{6.08 \times 10^{23}}

Explanation:

Data:

I = 2.15 A

t = 8 min 24 s

T = 26.0 °C

V = 65.4 mL

p = 774.2 To

1. Write the equation for the half-reaction

2H₂O ⟶ O₂ + 4H⁺ + 4e⁻

2. Calculate the moles of oxygen

p = \text{774.2 To} \times \dfrac{\text{1 atm}}{\text{760 To}} = \text{1.0187 atm}

V = 0.0654 L

T = (26.0 + 273.15) K = 299.15 K

\begin{array}{rcl}pV& = & nRT\\1.0189 \times 0.0654 & = & n \times 0.08206 \times 299.15\\0.06662 & = & 24.55n\\\\n & = & \dfrac{0.06662}{24.55}\\\\n & = & 2.714 \times 10^{-3}\\\end{array}

3. Calculate the moles of electrons

\text{n} = \text{2.714 $\times 10^{-3}$ mol oxygen} \times \dfrac{\text{4 mol electrons}}{\text{ 1 mol ozygen}} = \text{ 0.01086 mol electrons}

4. Calculate the number of coulombs

t = 8 min 24 s =504 s

Q = It = 504 s × 2.10 C·s⁻¹= 1058 C

5. Calculate the number of electrons

\text{No. of electrons} = \text{1058 C} \times \dfrac{\text{1 electron}}{1.602 \times 10^{-19}\text{ C}} = 6.607 \times 10^{21}\text{ electrons}

6. Calculate Avogadro's number

N_{\text{A}} = \dfrac{6.607 \times 10^{21}}{0.01086} = \mathbf{6.08 \times 10^{23}}\\\\\text{The experimental value of Avogadro's number is } \boxed{\mathbf{6.08 \times 10^{23}}}

3 0
3 years ago
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