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spayn [35]
3 years ago
15

The nervous system produces a response in your body in about 10 seconds. O A. True OB. False

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
7 0

Answer:

False

Explanation:

It takes a bout 0.3 seconded for your body to response

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It may seem strange that the selected velocity does not depend on either the mass or the charge of the particle. (For example, w
Charra [1.4K]

Answer:

b) q large and m small

Explanation:

q is large and m is small

We'll express it as :

q > m

As we know the formula:

F = Eq

And we also know that :

F = Bqv

F = \frac{mv^{2} }{r}

Bqv = \frac{mv^{2} }{r}

or Eq = \frac{mv^{2} }{r}

Assume that you want a velocity selector that will allow particles of velocity v⃗  to pass straight through without deflection while also providing the best possible velocity resolution. You set the electric and magnetic fields to select the velocity v⃗ . To obtain the best possible velocity resolution (the narrowest distribution of velocities of the transmitted particles) you would want to use particles with q large and m small.

6 0
4 years ago
Can I get a direct answer please??
OleMash [197]
Get a direct answer of what???
7 0
4 years ago
Technician A says that if starter drive clearance is too small, the starter will produce a noise during cranking. Technician B s
Ronch [10]

Answer:

Both Technicians A and B are wrong in there answers.

Explanation:

Starter Drives are rotating mechanical component use to drive another component (flywheel) to start an engine. And thus they are known as starters. Starters are smaller than the component they drive. They are found commonly in automobiles.

The starter and the driven component(gear) are supposed to fit closely, with some clearance between the two gears so as to operate without noise. When the<u> clearance is too small </u>there will be a <u>noise after cranking,</u>  and   when the <u>clearance is too great</u> there be <u>noise before cranking</u>.

Cranking simply means starting an engine or the initial rotating of an engine to start it.  

8 0
4 years ago
A 0.40 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.0 m on a frictionless horizontal su
DerKrebs [107]
<span>The centripetal force for such an arrangement can be found through the equation Fc = mv^2/r where m is the mass of the rotating object, v is that object's velocity, and r is the radius of rotation. In this case, we know that the maximum Fc that can be tolerated by the cord is 64N. Thus we set the equation up and solve for the value of v for which Fc = 64.
   64 = 0.4*(v^2)/1
 64/0.4 = 160 =
v^2 v = sqrt(160) = 12.65 m/s

   At any speed faster than 12.65 m/s, the cord will break.</span>
3 0
3 years ago
Please answer this as soon as possible
Alinara [238K]
I think it’s the third one, if not it’s the first.
4 0
3 years ago
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